[Adapted from https://krugernationalpark.co.za] 

Gates and camp  

distances

Berg-en-dal

Lower Sabie

Malelane

Numbi Gate

Orpen

Satara

Skukuza

Berg-en-dal 

- 

113 

12 

97 

213 

165 

172

Lower Sabie 

113 

- 

105 

95 

141 

93 

43

Malelane 

12 

105 

- 

94 

204 

156 

64

Numbi Gate 

97 

95 

94 

- 

195 

147 

54

Orpen 

213 

141 

204 

195 

- 

48 

137

Satara 

165 

93 

156 

147 

48 

- 

84

Skukuza 

172 

43 

64 

54 

137 

84 

-

• The Vineyard Race in February (75 miles) 
• The Ocean-to-Ocean Race in March (114,3 km) 
• The Karoo Fun Race in April (271 km) and 
• The Charity Fun Sprint (148,1 km) was his last participation in June.

NOTE: 1 km = 0,6214 miles

The map below shows the national roads of South Africa. 

[Adapted from https://images.google.co.za] 

➢ Inland: R22,49 

➢ Coastal: R21,77

[Source: AA Petrol price January 2024] 

The speed limit inside the park is: 

• 50 km/h on tarred roads 
• 40 km/h on gravel roads 

Gate times: 

• Entrance gates open at 05:30 
• Camp gates open at 04:30 
• All gates close at 18:30 

ANNEXURE B shows a part of a map of the Kruger National Park and  

TABLE 2 shows the distances between camps and gates. 

In a Mathematical Literacy classroom, a teacher keeps coloured pencils in three  identical cylindrical containers. These pencils remain in the containers until they  are used or lost. Below is an example of an image of the container with the coloured pencils and the diagram of the cylindrical container.  

(Diagram NOT drawn to scale.)

Example of image of container  with coloured pencils

Diagram of cylindrical container with dimensions 

Dimensions of the box are: 

Length = 38,8 cm 

Width = 27,5 cm 

Height = 30 cm 

 Electricity has become a scarce resource in South Africa. As a result, the country  is investigating alternative sources of generating electricity. One alternative  source of generating electricity is a wind turbine using rotating blades as shown  in the picture and diagram below. 

Image of wind turbine                                   Diagram of wind turbine 

The wind turbine is mounted on the top of a 50 m high tower. 

The length of each blade is 31 m. 

Dimensions: 

Radius = 30 cm 

Height = 45 cm 

 d 

Dimensions: 

Diameter = 10 cm 

Height = 20 cm 

NOTE: 

Area of a circle = 3,142 × radius²

Volume of a cylinder = 3,142 × radius² × height 

[Source: www.google.com ] 

Symbol 

Explanation

M 

Method

M/A 

Method with accuracy

CA 

Consistent accuracy

A 

Accuracy

C 

Conversion

S 

Simplification

RT/RG/RD/RM 

Reading from a table/graph/diagram/map

SF 

Correct substitution in a formula

O 

Opinion/Explanation//Reasoning

P 

Penalty, e.g. for no units, incorrect rounding off etc. 

R 

Rounding off

NPR 

No penalty for rounding 

AO 

Answer only

MCA 

Method with consistent accuracy

RCA 

Rounding consistent with accuracy

KEY TO TOPIC SYMBOL: 

F = Finance; M = Measurement; MP = Maps, plans and other representations; P = Probability

QUESTION 1 [20 MARKS] ANSWER ONLY FULL MARKS

Ques. 

Solution 

Explanation 

Level

1.1.1 

The perimeter of a shape is the total distance around  the edges defining the outline of that shape.  ✓✓A 

OR 

Total distance around the shape.  ✓✓A

2A correct explanation 

(2)

M 

L1

1.1.2 

Length of wall = 370/100 ✓C  

 = 3,7 m  ✓A

1C convert cm to m 

1A correct answer 

(2)

M 

L1

1.1.3 

P = length + length + height + height = 3,7 + 3,7 + 2,1 + 2,1 

 = 11,6 m ✓CA✓M

CA from 1.1.2 

1M adding correct values 1CA correct answer from 1.1.2   (2)

M 

L1

1.2.1 

Distance cycled =75 / 0,6214 ✓MA 

 = 120,6952044 ✓A

 ≈ 120,7 km 

Accept: 121 km / 120,695 km 

1MA dividing correct values 1A correct answer 

NPR 

(2) 

M 

L1

1.2.2 

Total distance logged: 

= 120,7 km + 114,3 km + 271 km + 148,1 km ✓M 

= 654,1 km ✓CA

Accept 654,4 km / 654,095 

CA from 1.2.1 

1M adding correct values 1CA correct answer 

(2)

M 

L1

1.3.1 

Pniel ✓✓RT

2RT reading from map (2)

MP 

L1

1.3.2 

5 water points ✓✓RT

2RT correct answer (2)

MP 

L1

1.3.3 

N1 ✓✓RT

2RT correct answer (2)

MP 

L1

1.3.4 

SW or Southwest ✓✓RT

2RT correct direction (2)

MP 

L1

1.3.5 

Helshoogte Pass ✓✓RT

2RT correct answer (2)

MP 

L1

[20]

QUESTION 2 [24 MARKS]

Ques. 

Solution 

Explanation 

Level

2.1.1 

Bar Scale ✓✓A OR Linear Scale ✓✓A OR Graphic ✓✓AScale 

2A identifying correct  scale  (2)

MP 

L1

2.1.2 

N6 ✓RT and N1 ✓RT 

1RT first national road 1RT second national  road 

Accept any order  (2)

MP 

L1

2.1.3 

North ✓A 

North East OR NE  ✓A

1A first direction 

1A second direction  (2)

MP 

L2

2.1.4 

His wife will be crossing the border between two countries and therefore needs a passport.  ✓✓O 

OR 

His wife will enter another country. ✓✓O

2O opinion 

(2)

MP 

L4

2.1.5

 ✓M 

% difference = (R22,49 – R21,77) ÷ R21,77× 100% ✓M ✓A 

= 3,307% ✓CA 

Statement is invalid – it will cost less than 4%  ✓O 

OR 

✓M  

% difference = ((R22,49 × 75) – (R21,77 × 75)) ÷ (R21.77 × 75)× 100% ✓M ✓A 

 = (1 686,75 – 1 632,75) ÷ 1 632,75 × 100% 

 = 3,307%  ✓CA 

Statement is invalid – it will cost less than 4%. ✓O

1M subtracting correct  values 

1M multiplying with  100% 

1A correct denominator 1CA simplification 

1O opinion 

OR 

1M subtracting correct  values 

1M multiplying with  100% 

1A correct denominator 1CA simplification 

1O opinion 

(5)

F 

L4

2.2.1 

Staff working at the gates need to go home. ✓✓O 

OR 

The wild animals in the park make it unsafe to travel or  be in unprotected parts during the night. ✓✓O 

OR 

Animals are not visible in the dark, park/camp gates open when people can see the animals. ✓✓O 

OR 

Access control  ✓✓O 

OR 

To avoid overcrowding  ✓✓O

OR 

Security reasons  ✓✓O 

OR 

So that people travelling from far or within the Kruger  National Park, can plan ahead. ✓✓O 

OR 

Accept any other valid reason. 

2O reason 

(2)

MP 

L4

2.2.2 

Other camps = 5 

Main camps = 7 ✓RT 

Difference = 7 – 5 = 2  ✓CA

1RT number of both camps 

1CA difference with 1  

correct camp AO (2)

MP 

L2

2.2.3 

Distance = speed × time ✓RT 

54 km = 50 km/h × time  ✓SF 

Time on gravel road 

follows do not  

= 54 km / 50 km/h  ✓S 

= 1,08 h 

= 1h 4 min 48 sec ✓C 

Time he will arrive at the gate is: 17:15 + 1:4:48 = 18:19:48  ✓CA

If calculated as  

1h05min 

17:15 + 1h05min 

= 18:20 

1RT distance 

1SF substitution with 50  km/h 

1S change the formula 

1C converting time 

1CA arrival time 

(5)

MP 

L3

2.2.4 

The roads are not so busy / people drive slower / more animals are  visible. ✓✓O 

OR 

It is the scenic route. ✓✓O 

OR 

To experience a sense of adventure. ✓✓O 

OR 

Gravel roads give you more access (short cut) to different parts of  the park. ✓✓O 

OR 

The route blends in with nature and gives a more authentic  bushveld experience. ✓✓O

OR 

Accept any other reasonable answer. 

2O reason (2)

MP 

L4

[24]

QUESTION 3 [36 MARKS]

Ques. 

Solution 

Explanation 

Level

3.1.1 

Number of coloured pencils across 

= 83 ÷ 6 ✓M = 13,833333… ✓CA ≈ 13 pencils ✓R 

Number of coloured pencils down 

= 22 ÷ 16,7  ✓M = 1,317365269 ≈ 1 pencil ✓R 

Total number of pencils in one container 

= 13 × 1 = 13 pencils ✓CA 

Number of pencils in 3 containers 

= 13 × 3  ✓M = 39 pencils ✓CA 

⸫ Correct  ✓O

1M dividing diameters 1CA simplification 

1R number of pencils 

1M dividing heights 

1R number of pencils 

1CA number of pencils  in one container 

1M multiply by 3 

1CA total number of  pencils 

1O opinion 

(9)

M 

L4

3.1.2 

Probability of taking a purple pencil from a container ✓A 

= 6 / 39 ✓A = 0,153846153 ≈ 0,154 ✓R

CA from 3.1.1 

1A numerator 

1A denominator 

1R 3 decimal places 

(3)

P 

L2

3.2.1 

(a)

Area of rectangle = length × width 

 = 150 mm × 120 mm  = 18 000 mm2✓C ✓SF ✓A

1C convert to mm 

1SF substitution 

1A area of rectangle 

(3)

M 

L2

(b) 

Area of circle = π × radius²

= 3,142 × 402 ✓A  = 5 027,2 mm² ✓CA 

OR 

= 3,142 × 40 × 40 ✓A = 5 027,2 mm² ✓CA 

Area without photo = 18 000 mm2– 5 027,2 mm²✓M 

 = 12 972,8 mm² ≈ 12 973 mm²✓CA

CA from 3.2.1 (a) 

1A radius 

1CA area of circle 

1MCA subtracting two  areas  

1CA rounding to nearest  mm2 

(4)

M 

L3

3.2.2 

Surface area of gift box 

= 2 (length × width) + 2 (width × height) + 2 (length × height) = 2 (38,8 × 27,5) + 2 (27,5 × 30,0) + 2 (38,8 × 30,0) ✓SF✓A 

= 2 134 + 1 650 + 2 328 ✓S 

= 6 112 cm² ✓CA

1SF substitution 

1A correct values 

1S simplification 

1CA surface area 

(4)

M 

L2

3.3.1 

Diameter = 31 m × 2  ✓M  = 62 m  ✓A

1M multiply radius by 2 1A correct diameter 

(2)

M 

L2

3.3.2 

Maximum height = 50 m + 31 m   = 81 m ✓MA ✓A

1MA adding correct  

values 

1A answer (2)

M 

L2

3.3.3 

Circumference = 2 × π x radius 

 = 2 × 3,142 × 31  ✓SF 

 = 194,804 × 2 = 389,608 m ✓MA

1SF substitution 

1MA multiply by 2 and  answer 

NPR (2)

M 

L2

3.3.4 

Number of households = 1 750/25 ✓M  

= 70 households  ✓A

1M dividing by 25 

1A correct answer 

(2)

M 

L1

3.4 

Volume of 2 cylindrical basins used three times a day = π × r² × h  

✓SF✓M 

= (3,142 × 302 × 45) × 2 × 3  = 763 506 cm³✓CA 

Litres of water used daily 

=763 506 / 1 000× ¾  ✓C  

= 572,6295 litres  ✓CA 

OR 

Volume of 2 cylindrical basins used three times a day = π × r² × h  

✓SF✓M 

= (3,142 × 302 × 45) × 2 × 3  = 763 506 cm²

✓CA 

Litres of water used daily 

= 763 506 × ¾ = 572 629,5 cm3 = 572 629,5 ✓C

= 572,6295/1 000  litres  ✓CA 

1SF substitution 

1M multiplying by 2 and 3 1CA volume  

1C converting to litres 1CA ¾ litres of water 

1SF substitution 

1M multiplying by 2 and 3 1CA volume of water 

1C converting to litres 1CA ¾ litres of water 

(5)

M 

L3

[36]

QUESTION 4 [20 MARKS]

Ques. 

Solution 

Explanation 

Level

4.1.1 

Total number of hours: 

Friday: 24:00 – 15:30 = 8,5 hours ✓A 

Saturday – Monday = 24 hours × 3 days = 72 hours  ✓A 

Tuesday = 10 hours  ✓A 

Total number of hours = 8,5 + 72 + 10 = 90,5 hours  ✓MA 

Invalid  ✓O

1A number of hours on  Friday 

1A number of hours for 3  days 

1A number of hours on  day of departure 

1MA adding correct  

values and correct  

answer. 

1O opinion 

(5)

M 

L4

4.1.2

radius = diameter / 2= 10 / 2= 5 cm ✓A 

Volume of cylinder = 3,142 × radius² × height 

 1 571 cm³ = 3,142 × 52 × height  ✓SF 

 Height = 1 571 / 78,55  ✓M 

 Height = 20 cm ✓CA

1A find radius 

1SF substitution 

1M change subject of the  formula 

1CA finding the height (4)

M 

L3

4.1.3 

Area of top and bottom surface = 78,55 cm² × 2 ✓M 

 = 157,1 cm² ÷ 100² ✓C 

 = 0,01571 m² ✓S 

Total cost = 0,01571 m² × R144,65 ✓M = R2,27 ✓CA 

OR 

Area of top = 78,55 cm² ÷ 100² ✓C  = 0,007855 m² 

✓S 

Cost of wood of top = 0,007855 × R144,65  ✓M

 = R1,13622575 

Total cost = R1,13622575 × 2  ✓M 

 = R2,27 ✓CA 

1M multiply by 2 

1C divide by 1002 

1S simplification of  

answer in m2 

1M multiply R144,65 1CA answer 

OR 

1C divide by 1002 

1S simplification of  

answer in m2 

1M multiply R144,65 1M multiply by 2 

1CA answer 

(5)

F 

L3

4.2.1 

Actual length = 3,4 cm × 65 ✓M

 = 221 cm ✓A 

1M multiply correct  

values and correct  

answer 

1A answer 

(2)

MP 

L2

4.2.2 

Probability = 3/7✓A

1A numerator 

1A denominator 

(2)

P 

L2

4.2.3 

The main bedroom.  ✓A 

Room is facing north. ✓O

1A correct room 

1O opinion 

(2)

MP 

L4

[20]

TOTAL: 100