SYMBOL

EXPLANATION

M

Method

MA

Method with accuracy

MCA

Method with consistent accuracy

CA

Consistent accuracy

A

Accuracy

C

Conversion

S

Simplification

RT/RG/RP

Reading from a table/graph/plan

SF

Correct substitution in a formula

O

Opinion/Example/Definition/Explanation

P

Penalty, e.g. for no units/incorrect rounding off, etc.

R

Rounding off

NPR

No penalty rounding or omitting units

AO

Answer only, if correct, full marks

Question 1 [31 MARKS]AO Full Marks

Ques

Solution

Explanation

T/L

1.1.1

Horizontal/double/compound/multiple ✓O bar graph ✓O

1O type
1O bar graph (2)

D
L1

1.1.2

                         ✓RT
71,6%; 51%; 10,3%; 7,3%; 6,6% ✓A

1RT reading all correct values
1A descending order
If Johannesburg is used max 1 mark (2)

D
L1

1.1.3

Step 6 ✓✓A

2A identifying correct Step 
Accept any identification in step 6 for Cape Town (2)

F
L1

1.1.4

Cape Town ✓✓A

2A stating Cape Town
Accept JHB Step 1 full marks (2)

F
L1

1.1.5

                           ✓RT
Cost = 3,5 kℓ × R7,14 = R24,99 ✓A

1RTfor R7,14
1Asimplification
CA only if R4,56 is used Accept R25 full marks (2)

F
L1

1.1.6

Numerical ✓✓A

2A stating numerical 
Accept numerically full marks (2)

D

L1

1.2.1

Selling price minus profit ✓✓A
OR
The amount of money needed (for raw material, labour, etc.) to make an item ✓✓A

2A correct definition
Accept:

• Amount  you  pay  for  buying stock/clocks
• Money you receive without profit.
• Price before mark-up is added. (2)

F

L1

1.2.2

               ✓RT                      ✓A
Cost price = R3 350 - R914 = R2 436

1RT correct values
1A simplification (2)

F
L1

Ques

Solution

Explanation

T/L

1.2.3

      ✓A
22:08✓A

1A correct hours
1A correct minutes (2)

M
L1

1.2.4

            ✓MA
Total profit = R914 + R60 + R573 + R1623
= R3170,00 ✓CA

1MA  adding all correct values
1CA simplification (2)

F
L1

1.3.1

Converting scale reading 
                ✓M
=394 g ÷ 1 000 = 0,394 kg ✓A

1M dividing by 1 000
1A simplification (2)

M
L1

1.3.2

             ✓M
New reading = 394 - 128
= 266g ✓A

1M subtracting correct values
1A simplification (2)

M
L1

1.3.3

     ✓M              ✓M                    ✓A
Peach =394 - 128 - (128  ÷ 2) = 394 - 192
= 202 g

OR

Plum = 128 g ÷ 2 ✓M
= 64 g ✓A
Peach = 266 g - 64 g ✓M
= 202 g

1M  subtraction from 394
1M dividing 128 by 2
1A for 192

OR

1Mdividing pear by 2
1A plum 64g
1Msubtracting two values  (3)

M
L1

1.3.4

0%  OR   0  OR⁰✓✓A
               3

2A solution
Accept impossible - full marks   (2)

P
L1

1.3.5

394g  :  128g ✓M
197  :  64 ✓A

1M concept of ratio
1A ratio without units
Accept:

• Reverse the order withsimplification one mark
• Unit ratio  1: 0,325 OR 3,08:1 one mark
• Correct fractional form - full marks (2)

M
L1

[31]

QUESTION 2 [38MARKS]

Ques

Solution

Explanation

T/L

2.1.1

December ✓✓A
OR
The twelfth month of the year ✓✓A
OR

The last month of the year    ✓✓ A

2A correct month
Accept:

• Mid Nov. to mid Dec.
  Nov / Dec
  12 (full marks)
• 8/9/15 Dec max one mark (2)

F

L1

2.1.2

The overall limit exceeded ✓✓A

2A correct code description
Accept:

• Owe supplier     
• Funds exhausted    (full marks)
• Code (870) only max one mark (2)

F

L1

2.1.3

Dr Dhlamini ✓✓RT

2RT name (2)

F
L1

2.1.4

                                                    ✓MA
Increased amount = R736,90 × 6,3  = R46,42
                                                  100
New price = R46,42 + R736,90 ✓MCA
= R783,32 ✓CA

OR

                             ✓MA
Increased percentage = 100% + 6,3% = 106,3%
New price = R736,90 × 106, 3 ✓MCA
                                        100
= R783,32 ✓CA

1MA calculating 6,3%
1MCA adding the values
1CA simplification

OR

1MA calculating 106,3%
1MCA multiplication
1CA simplification (3)

F

L2

Ques

Solution

Explanation

T/L

2.1.5

                             ✓ RT
Tax claimable = R5 326,66  - R445,10
= R4 881,56✓A

AO
1RT  correct values
1A Simplification (2)

F

L2

2.1.6

                                  ✓✓O
Money the member must pay to the suppliers.

2O for correct definition

F

L1

Accept: Full Marks

Amount of money not paid by

the scheme.

Money owed to the scheme.

(2)

2.1.7

Total amount              ✓RT                    ✓M

=R173,03 + R117,44 + R61,50 +R80,98 + R46,80
= R479,75

OR

Total amount      ✓RT            ✓M
= R1 661,75 - R736,90 - R445,10
= R479,75

1RT all correct values
1M adding values

OR

1RT all correct values
1M subtracting values (2)

F

L1

2.2.1

Value Added Tax ✓✓A

2A acronym written out (2)

F
L1

2.2.2

✓RT
VAT = R988,00 ×  14%   ✓M
                             114%
= R121,333333
≈ R121,33    ✓ A

OR

                       ✓RT
VAT = R988,00 ÷1,14 × 0,14 ✓M
= R121,333333
≈ R121,33 ✓A

OR

                               ✓RT
VAT = R988 -  [R988] ✓M
                        [1,14 ]
=  R988 - R866,666..
≈  R121,33 ✓A

1RT using correct value 
1M multiplying by 14%
                            114%
1A Simplification

OR

1RT using correct value
1M dividing by 1,14 and multiplying by 0,14
1A Simplification

OR

1RT using correct value

1M dividing by 1,14 and subtracting
1A Simplification (3)

F

L2

Ques

Solution

Explanation

T/L

2.2.3

Difference = R223 - R13 ✓M
= R210 ✓A

AO
1M subtracting correct values
1A simplification
Accept:

• R210 full marks (2)

F

L1

2.3.1

Exchange rate
                          ✓✓RT
R1 = 0,797782 Botswana pula
OR
               ✓✓RT
1BWP = R1,253475

2RT correct exchange rate

(2)

F

L1

2.3.2

Rupee✓A
Dinar ✓A
Yen ✓A

1A rupee
1A dinar
1A yen
Accept:

• Currency values or name of country -  max 2 marks (3)

L1

F

2.3.3

a

Cost price = ZAR 13 × 0,797782 ✓M
= BWP 10,37 ✓A
OR
                          ✓M
Cost price  = 13 ZAR ÷ 1,253475
= BWP 10,37✓A

AO
CA from Q2.3.1 if ratio listed
1M multiplying correct values
1A Simplification

OR

1M dividing correct values
1A Simplification
No penalty for unit (2)

F

L2

2.3.3

b

Profit = (SP - CP) × number sold
7 526  =  (48 - 10,37) × number sold 
               ✓ SF
Number sold  × 37,63 = 7 526 ✓CA
Number sold =  7526 ✓MCA
                         37,63
= 200 ✓CA

CA from Q2.3.3a
1SF substitution
1CA simplification
1MCA dividing
1CA simplification (4)

F

L3

Ques

Solution

Explanation

T/L

2.3.4

Number of shares 3+2 =5✓A
Errol’s share of the profit
= 2  × BWP 7 526 ✓M
   5
= BWP 3 010,40  ✓CA

AO
1A for calculating 5
1M multiplying correct values
1CA Errol’s profit share
No penalty for units (3)

F

L2

2.3.5

                                 ✓A
Algerian dinar =      1      
                        9,546785 ✓A
= 0,104747

1Anumerator
1Adenominator (2)

F

L2

[38]

QUESTION 3 [21 MARKS]

Ques

Solution

Explanation

T/L

3.1.1

Number of pallets = 12 × 2✓MA
= 24✓A

AO
1MA  multiply 12 by 2
1A  simplification (2)

M

L1

3.1.2

Height of the table ✓RT
=145mm + 145mm + 200mm ✓M
= 490 mm ✓CA

1RT  using correct values
1M  adding correct values
1CAsimplification
Accept:

• adding 145 and 200 max 2  marks (3)

M

L1

3.1.3

Area = length × width
✓RT
= 1 200 mm × 1050 mm ✓SF
= 1 260 000 mm²✓CA

1RT reading of correct values
1SF  substituting correct values
1CA simplification (3)

M

L2

3.1.4

Perimeter of glass top
                ✓RT                    ✓M
= 1200mm + 1050mm +1200mm + 1050 mm
= 4 500 mm ✓CA

OR

                          ✓M
Perimeter  = 2 × (length + width)
= 2 × (1 200 mm + 1 050 mm )              ✓SF
= 2 × 2 250 mm
= 4 500 mm                    ✓CA

AO
1RT reading all correct values
1M adding correct values
1CA simplification

OR

1M correct formula
(P = 2L + 2B)
1SF substitution
1CA simplification (3)

M

L1

Ques

Solution

Explanation

T/L

3.2.1

Length of ribbon
= π × diameter + overlap
        ✓C           ✓SF
= 3,142 × 11cm  + 2cm
= 36,562 cm ✓✓CA

OR

Length of ribbon
= π × diameter + overlap
= 3,142 × 110 mm  + 20 mm✓SF
=  365,62 mm ✓✓CA
= 36,562 cm ✓C

1C converting diameter to 11 cm
1SF substituting in formula
2CA simplification

OR

1SF substituting in formula
2CA simplification in mm
1C converting to cm
Accept 37 cm  full marks (4)

M

L2

3.2.2

a

Inner diameter  = 110 - 5 - 5
                              ✓MA
Inner radius      = 100 mm ÷ 2
= 50 mm ✓CA
OR
Inner radius = 55mm  - 5 mm ✓MA
= 50 mm ✓CA

AO
1MA  subtracting 5 twice and dividing by 2
1CA simplification
OR
1MA  subtracting 5 from the radius
1CA simplification (2)

M

L1

3.2.2

b

Volume of cylinder
= π × radius² × height
               ✓   SF            ✓A
= 3,142 × (50mm)² × 48mm   
                ✓ CA
= 377 040mm³✓A

CA from Q3.2.2 a
1A for calculating 48
1SF substituting radius from Q3.2.2a
1CA simplification
1A for correct unit (4)

M

L2

[21]

QUESTION 4 [25MARKS]

Ques

Solution

Explanation

T/L

4.1.1

7 ✓✓RP

2RP correct store number
Accept Shop number 9 full marks (2)

MP

L1

4.1.2

Parking 2 ✓✓RP

2RP correct parking number
Accept 2 full marks (2)

MP

L1

4.1.3

Woolworths✓✓RP

2RP correct shop name
Accept:

• Woolworths with additional shop maximum 1 mark (2)

MP

L1

4.1.4

Turn right as you exit the Crazy Daisy Shop✓A
Turn righttowards Entrance 1
Turn lefttowards Entrance 2    ✓A
Pass two shopsthen turn right    ✓A
Shop number 18 will be on your right ✓A

OR

Turn right as you exit the Crazy Daisy Shop ✓A

Turn right towards Entrance 1
Continue straight towards Entrance 1 ✓A

✓A

Turn left passing Checkers heading towards Entrance 4
Then turn left towards shop 18 ✓A

1A turn right
1A turn left
1A turn right
1A on your right

OR

1A turn right
1A continue straight
1A turn left
1A turn left
Accept:

• Using shops as landmarks (4)

MP

L2

Ques

Solution

Explanation

T/L

4.1.5

27 doors ✓✓A

2A correct number of doors (2)

MP
L2

4.1.6

                      ✓A
P_{(2 entrances)} =  2  / 0, 087 / 8, 7%
                        23  ✓A

1A numerator
1A denominator
Accept:
Full Marks for   3 
                        23

Max 1 mark for  3   (2)
                         21

P

L2

4.1.7

                                        ✓A
P_{(not an even number)} =    12   
                                      23   ✓CA

1A numerator
1CA denominator from Q4.1.6
Accept as CA from Q4.1.6
Full Marks for  11   (2)
                        21

P

L2

Ques

Solution

Explanation

T/L

4.2.1

Top view of the coffee shop. ✓✓A
OR
Top view ofthe shop without the roof. ✓✓A

2A explanation
Accept:

• Aerial view without the roof
• Layout of a home from above (2)

MP

L1

4.2.2

Bathroom OR Wash roomOR Rest room ✓✓RP

2RP reading from plan
Accept:

• Toilet, Cloak room, Ablution, Loo, Ladies, Gents (2)

MP

L1

4.2.3

South-East  / SE      ✓✓RP

2RP reading from plan (2)

MP

L1

4.2.4

70 mm : 15 m
70  : 15 000 ✓C
1 : 214,2857143    ✓S
1 : 214 ✓CA

1C convert to mm
1S simplification
1CA answer
Accept 1 : 215 (3)

MP

L3

[25]

QUESTION 5 [35 MARKS]

Ques

Solution

Explanation

T/L

5.1.1

September ✓✓RT

2RT  read from table
Accept:

• Sep/Sept/ 9^th month full marks
• September and another month maximum 1 mark (2)

D

L1

5.1.2

Mean income
                                                      ✓RT
= (238 + 266+254+238+233+216+247 +251+275+269+254+198)million
                                                        12
=2939million        ✓M
      12
= R244,9166667 million /  R244 916 666,7 ✓CA

1RT correct values
1M  concept of mean
1CA  answerin millions
Omitted millions Max 2 marks (3)

D

L2

5.1.3

                     ✓RT
   743   ×  100% ✓M
  12343      1
= 6,02% ✓CA

1RT  correct values
1M  multiply by 100
1CA  simplify (3)

D

L1

5.1.4

45 905 000 ✓✓RT
OR
45 905 thousand ✓ RT

2RT correct value from table
45 905 only max 1 mark (2)

D

L1

5.1.5

                                  ✓RT
Sixty five million one hundred and sixty eight thousand ✓A

1RT reading from table as is 1A  correct wording with millions (2)

D

L1

5.1.6

                               ✓MA
Median = 1015+1020 ✓M
                         2
= 1 017, 5 million ✓CA

AO
1MAidentifying correct middle values
1M  concept of  median
1CA  simplification
Penalty 1 for omitting millions (3)

D

L2

5.1.7

                             ✓A

P_{(less than 200  000 000)} =  1  
                                       12 ✓A
= 0,08333333 CA

AO
1A numerator
1A denominator
1CA decimal form
NPR (3)

P

L2

Ques

Solution

Explanation

T/L

5.1.8

D

L2

1A  for each correctly plotted bar × 6
If graph is drawn on top of other graph (full marks)
Perfect line graph (3/6) (6)

Ques

Solution

Explanation

T/L

5.2.1

Total number of households for Grants:
                ✓M                          ✓MA
= [2768- (1404+216+123+180+7+117+7)] thousand
=  714 000 households ✓CA
OR
           ✓M                                      ✓MA
(2768 - 1404 - 216 - 123 - 180 - 7 - 117 - 7) thousand
=  714 000 households ✓CA

1M  subtracting from 2 768
1MA adding values
1CA  simplification
OR
1M  subtracting from 2 768
1MA continuous subtraction
1CA  simplification (3)

D

L1

5.2.2

Business ✓✓RG

2RG  correct source (2)

D

L1

5.2.3

Difference
                    ✓RT
=216 000 - 28 000 ✓M
=  188 000✓A

AO
1RT  correct values
1M subtracting
1A simplification
Penalty 1 for omitting thousands (3)

D

L1

5.2.4

Remittance
                 ✓RT
=  64000  ×  100 % ✓M
    532000      1
= 12,03% CA

1RT correct values
1M percentage
1CA simplification
     64     ×  100% =0, 012
532000        1
maximum 2 marks (3)

D

L2

[35]

TOTAL: 150 MARKS