Symbol 

Explanation

M 

Method

MA 

Method with accuracy

CA 

Consistent accuracy

A 

Accuracy

C 

Conversion

S 

Simplification

RT 

Reading from a table/graph/document/diagram

SF 

Correct substitution in a formula

O 

Opinion/Explanation

P 

Penalty, e.g. for no units, incorrect rounding off, etc.

R 

Rounding off

NPR 

No penalty for rounding

AO 

Answer only

MCA 

Method with constant accuracy

QUESTION 1 [32 MARKS] ANSWER ONLY FULL MARKS

Q/V 

Solution

Explanation

T&L

1.1.1 

✔✔A    1 / one
OR
A day / 'n dag   ✔✔A 
OR  ✔✔A
One day 

2A for correct day  (2)

M 

L1

1.1.2 

Price before saving  ✔M 
R70 + R250  ✔A
= R320 

1M adding correct values 
1A simplification  (2)

F 

L1

1.1.3

Ariel ✔✔A

2A product   (2)

F 

L1

1.1.4 

                  ✔MA 
750 m ℓ ÷ 1 000  
= 0,75 ℓ  ✔A 
OR
                 ✔MA 
750 m ℓ × 0,001  
= 0,75 ℓ   ✔A

1MA for dividing by 1 000 
1A simplification only if division

OR

1MA for multiplying by 0,001 
1A simplification only if multiplied (2)

M 

L1

1.1.5 

Price  
= R11 × 3  ✔MA
= R33,00✔CA 

1MA multiplying correct values 1CA simplification  (only if R7,70× 3)  (2)

F 

L1

Q 

Solution

Explanation

T&L

1.1.6 

R11; R15; R18; R22; R30; R43; R44; R45; R65;  R250✔✔A

2A arranging in correct order
If names used max 1 mark (2)

D 

L1

1.2.1 

English = 35 letters OR 15 letters  ✔✔A

2A correct number  WC, FS, NC Provinces  accept both  (2)

M 

L1

1.2.2 

44 0C ✔✔A

2A correct reading Accept 44 - 45 0C  (2)

M 

L1

1.2.3 

One unit on the drawing represents twenty five units  in reality ✔✔A
OR
Scale in this context means that the drawing of the  T-shirt is 25 times smaller than in reality . ✔✔A 
OR
On the picture the shirt is 25 times smaller  ✔✔A 

2A correct definition 
Accept no units (2)

MP 

L1

1.2.4 

± 61 mm ✔✔A

2A correct measurement (Accept 59 mm – 64 mm) \
Correct answer in cm =  max 1 mark (2)

M 

L1

Q 

Solution

Explanation

T&L

1.3.1

Two Oceans Marathon ✔✔RT

2RT reading from table 
Accept: 

• Race on 15 April 2017
• Race of 56 km
• Race with an entry fee of  R520,00  (2)

M 

L1

1.3.2

Comrades Marathon  ✔✔RT

2RT reading from table 
Accept: 

• Race on 4 June 2017
• Race of 89 km
• Race with an entry fee of  R460,00   (2)

M 

L1

1.3.3

R520,00 – R460,00  ✔RT 
= R60,00 ✔A

1RT correct values from the   table 
1A answer  (2)

F 

L1

1.4.1 

12 Hours  ✔✔A

OR

Half a day ✔✔A 

2A correct time 
Accept: 

• 12:00 OR/OF
• 12 o’clock 

Max 1 mark (2)

M 

L1

1.4.2 

Discrete ✔✔A

2A discrete  (2)

D 

L1

1.4.3

   ✔RT      ✔A
17 031 : 13 852 

1RT correct values from  table 
1A correct values in correct   order 
Accept answer as unit   ratios: 

• 1 : 0,813
• 1,229 : 1 

Accept answer in fraction  form NPR  (2)

D 

L1

[32]

QUESTION 2 [41 MARKS] 

Q

Solution 

Explanation

T&L

2.1.1

Interest refers to the amount that will be added to an  ✔A  account that is not settled yet
OR
Extra amount is charged on the late payments  ✔A 
OR
Extra money to be charged on overdue fees ✔A 
OR
Money charged for not paying fees on time ✔A 
OR
Interest in this context is the charge levied because of  unpaid fees or late payment of fees ✔A 

1A amount charged 
1A reason  (2)

F 

L1

2.1.2 

R14 819,50 ✔✔RT

2RT balance  (2)

F 

L1

2.1.3

                   ✔RT 
   148,20   ×   100 %  ✔M
14 819,50         1 
= 1,000033739329937 
≈ 1%  ✔CA 

1RT correct values 
1M multiply by 100 
1CA answer  (3)

F 

L2

Q 

Solution

Explanation

T&L

2.1.4 

                          ✔RT
APG 2039W Design & Theory Studio II✔RT 

1RT code 
1RT name 
If APG omitted = full marks (2)

F 

L1

2.1.5

                   ✔RT                              ✔M 
R14 967,70 – R8 650,00  = R6 317,70 

1RT correct values 
1M subtracting deposit  (2)

F 

L1

2.1.6 

                                 ✔RT                ✔M 
Total amount  = R3 030 + R3 030 + R2 280 + R2 280 + R9 580 +   R4 530 + R29 460 + R2 087 + R395,95 +   R395,95   ✔CA 
= R57 068,90  
OR
Total amount 
               ✔M                   ✔RT 
= R62 594 – R6 317,70 + 2 × R395,95   = R57 068,90  ✔CA 
OR
Total amount 
               ✔RT               ✔M 
R40 386 + R23000 + R8650 – R14819,50 – R148,50 = R57 068,90   ✔CA 
OR
Total amount 
            ✔RT                                 ✔M 
R3 030 + R3 030 + R2 280 + R2 280 + R9 580 +  R4 530 + R29 460 + R395,95 + R395,95 = R54 981,90    ✔CA 
OR
Total amount 
                      ✔M                                     ✔RT 
= R62 594 – R6 317,70 + 2 × R395,95 − R2 087 = R54 981,90  ✔CA 
OR
Total amount 
                ✔RT                     ✔M  
R40 386 + R23000 + R8650 – R14819,50 – ✔CA 
R148,50 − R2 087 = R54 981,90 

AO 
1RT reading all correct values
1M adding values 
1CA simplification 

OR

1RT reading all correct values
1M subtracting values 
1CA simplification 

OR

1RT reading all correct values
1M subtracting values 
1CA simplification 

OR

1RT reading all correct values
1M adding values 
1CA simplification 

OR

1RT reading all correct values
1M subtracting values 
1CA simplification 

OR

1RT reading all correct values
1M subtracting values 
1CA simplification 

F 

L1

Q 

Solution

Explanation

T&L

2.1.7 

Direct deposit \ ✔✔RT

2RT reading correctly 
Accept deposit only  (2)

F 

L1

2.1.8 

Monthly instalment 
R40 386,60 ÷ 5  ✔A 
= R8 077,32  ✔M
OR
Monthly instalment ✔A  
R8 077,32 × 5  ✔M 
= R40 386,60 
OR
Monthly instalment 
R40386,60  ✔M 
R8077,32  
= 5  ✔A

1A calculating 5 
1M dividing by 5 
OR
1A calculating 5 
1M multiply by 5 
OR
1M dividing correct values in  correct order 
1A calculating 5  (2)

F 

L1

2.2.1 

Inflation is a measure of rate at which the cost of goods  is changing over a period of time and is usually  ✔A  expressed as a percentage ✔A
OR
The percentage increase of the food prices over the  ✔A  period 1970 – 2015 ✔A
OR
Percentage increase of price over a period of time  ✔A
OR
Inflation is the rising price of goods/items over time ✔A

1A percentage increase 
1A time  (2)

F 

L1

Q

Solution

Explanation

T&L

2.2.2 

R0,30 OR/OF 30c ✔✔RT

2RT correct value 
Accept 0,30 
If the candidates only   wrote 30 = max 1 mark  (2)

F 

L1

2.2.3 

✔M   R557,00 – R418,00   ✔RG 
= R139,00✔CA 

AO 
1RG correct amount 
1M subtracting 
1CA simplification (one of the 2  values must be correct) (3)

F 

L1

2.2.4 

Percentage change
        ✔RT 
R75,00 R0,25  ×    100%    ✔SF 
      R0,25                 1 
= 29 900 %   ✔CA 
OR
Percentage change 
          ✔RT
  75   × 100% = 30 000%  ✔M 
0,25 
Therefore % increase = 30 000% - 100%  ✔CA
= 29 900% 

AO 
1RT all correct values 
1SF substitute correct values 
1CA correct percentage 
OR
1RT all correct values 
1M subtracting 
1CA correct percentage  (3)

F 

L2

Q

Solution

Explanation

T&L

2.2.5 

Cost price
  100   ×  104,90  ✔MA 
117,5 
= R89,28   ✔A 
OR
Cost price 
104,90  ✔MA 
117,5% 
= R89,28   ✔A 
OR
Cost price  
104,90  ✔MA 
1,175 
= R89,28  ✔A 
OR
Cost price 
 17,5 × R104,90 = R15,62  ✔MA 
117,5 
R104,90 – R15,62 
=R89,28  ✔A

AO 
1MA multiplying correct values
1A answer 
OR
1MA dividing correct values    in the correct order
1A answer 
OR
1MA dividing correct values  in the correct order 
1A answer 
OR
1MA multiplying and subtracting  correct values 
1A answer  (2)

F 

L2

2.3.1 

B OR/OF R241 600 000 000 ✔✔A 

2A correct value  (2)

F 

L1

Q

Solution

Explanation

T&L

2.3.2 

Budget is the proposed way in which money will be  spent on different items ✔✔A 
OR
A plan on how money is going to be spent on  estimated income ✔✔A 
OR
A plan in how money is going to be spent ✔✔A 
OR
Financial plan how to spend money/finance  ✔✔A 
OR
Estimated income and expenditure of money ✔✔A

2A definition  (2)

F 

L1

2.3.3 

Skills development levy institutions s✔✔RT

2RT correct sector  (2)

F 

L1

2.3.4 

Percentage of the total education budget
✔RG/RT 
 15,3  × 100%   ✔M 
320,5 
= 4,77%   ✔CA 
OR
Percentage of the total education budget
✔RG/RT 
 R15 300 000 000    × 100 %  ✔M
R 320 500 000 000       1 
= 4,77%   ✔CA 

1RG/RT correct values 
1M multiply by 100 
1CA answer 
OR
1RG/RT correct values
1M multiply by 100 
1CA answer 
NPR  (3)

F 

L2

Q 

Solution

Explanation/ 

T&L

2.3.5 

Education Administration plus NSFAS amount  to 31,1 billion rand 
9,7% ✔✔A 
Accept any estimation from 9,5% but less than 9,86% Aanvaar enige skatting vanaf 9,5% maar minder as  9,86% 
OR
15,8 + 15,3 = 31,1 billion ✔M
= 9,7%   ✔A 
Accept any estimation from 9,5% but less than 9,86% 

AO 
2A correct estimation
OR
1M adding values 
1A estimated value  (2)

F 

L2

[41]

QUESTION 3 [18 MARKS] 

Q/V 

Solution

Explanation

T&L

3.1.1 

15 cm + 17 cm + 19 cm + 21 cm  ✔A 
= 72 cm × 10  ✔CA
= 720 mm  ✔M 

1A adding of correct values
1CA conversion 
1CA answer in mm  (3)

M 

L1

3.1.2a 

Diameter  = 2 × radius 
 = 2 × 14 cm  ✔M
 = 28 cm✔A 

AO 
1M multiplying by 2 
1A diameter  (2)

M 

L1

3.1.2b 

Volume of a cylinder = π × r² × height 
Volume of a cylinder = 3,142 × (14)² × 15 cm   ✔SF 
= 3,142 × 196 cm2 × 15 cm  ✔S
= 9 237,48 cm³  ✔CA 

AO 
1SF substitution 
1S squaring 14 
1CA simplification  (3)

M 

L2

3.1.3

The perimeter of a shape is the total distance around  the edges defining the outline of that shape  ✔✔A 
OR
Total distance around the shape  ✔✔A

2A explanation  (2)

M 

L1

3.1.4

Area of a rectangle = length × width  ✔SF
 = 15 cm × 12 cm 
 = 180 cm2✔CA 

1SF correct substitution  
1CA simplification  

• 35 cm × 33 cm = 1 155 cm2  Max 1 mark   (2)

M 

L2

3.2.1

Amount  in kg = 3,5 ÷ 2,25  ✔C 
 = 1,556  ✔A

1C conversion 
1A simplification 
Accept

• 1,56 kg ; 
•  1,6 kg
• 1,5 only = 0 marks  (2)

M 

L2

Q 

Solution/

Explanation

T&L

3.2.2

1 mℓ flour = 0,7 g flour 
625 × 0,7 g ✔C
  1 
= 437,5 g✔A 

1C conversion 
1A simplification (2)

M 

L2

3.2.3

°C = (°F – 32°) ÷ 1,8 
°C = (356° – 32°) ÷ 1,8  ✔SF
°C = (324°) ÷ 1,8  ✔A
 = 180 °C  

1SF correct substitution
1A simplification  (2)

M 

L2

[18]

QUESTION [24 MARKS]

Q

Solution

Explanation

T&L

4.1.1 

South West OR SW ✔✔A

2A direction (2)

MPL 

2

4.1.2 

Namaqua National Park✔✔RM

2RM national Park (2)

MPL 

1

4.1.3 

✔✔RM ✔RM
Keimoes, Kakamas, Pofadder 
(Any 2 of the 3) 

2RM first correct town 
1RM second correct town (3)

MPL 

1

4.1.4 

Ratio scale OR number scale OR numerical  scale ✔✔A

2A ratio / number / numerical 
Accept unit ratio  (2)

MP 

L1

4.1.5 

Measured distance /Gemete afstand = 135 mm ✔A 
 1 : 3 007 874 ✔M 
135 mm × 3 007 874 
= 406 062 990 mm 
= 406 062 990 ✔C
    1 000 000 
= 406 km  ✔R 
OR
         ✔A            ✔M 
13,5 cm × 3 007 874 
= 40606299cm   ✔C 
     100 000 
= 406,06299 km  ✔R
≈ 406 km 

1A measures distance 
1M using scale 
1C conversion 
1R to the nearest km 
(Range: 130 mm to 140 mm) 
OR
1A measures distance 
1M using scale 
1C conversion 
1R to the nearest km 
(Range: 13 cm to 14 cm) (4)

MPL 

3

4.2.1 

Voortrekker Road ✔✔RM 
OR
N14  ✔✔RM 

2RM correct road  (2)

MPL 

1

Q

Solution

Explanation

T&L

4.2.2 

Rivier Street ✔✔RM

2RM correct road   (2)

MP 

L2

4.2.3 

Debs-Lodge  ✔✔RM

2RM correct road  (2)

MP 

L2

4.2.4

Time  = 2,34 km   ✔SF 
             40 km/h  
= 0,0585 h × 60  ✔C
= 3,51 minutes✔CA 

1SF calculating time 
1C multiply by 60 
1CA simplification 
NPR  (3)

MP 

L2

4.2.5

P = 13    ✔A
      42
OR
0,310
OR
31% 
OR
1 − 29= 13  ✔A
      42   42

1A numerator (independent) 
1A denominator  
OR
1MA subtracting from 1 
1A simplification  (2)

P 

L2

[24]

QUESTION 5 [35 MARKS] 

Q

Solution

Explanation 

T&L

5.1.1

R2 085 600 000 ✔✔RT 
OR
R2 085,6 million✔✔RT 
OR
R2,0856 billion✔✔RT 

2RT correct amount  
Table value = max 1   mark  (2)

D 

L1

5.1.2

R1 323+ R2 085,6 +R3 162+R2 158 +R1 847 + R2 732  million    ✔RT  ✔CA 
                                            6 
= R2 217 933 333 OR R2 217,933333 million

AO 
1RT correct values 
1M concept of mean 
1CA simplification 
NPR  (3)

D 

L2

5.1.3

                ✔A                ✔A
Maximum = 46,1 thousand
OR
Maximum = 46 100✔✔RT 

1A correct value 
1A unit 
OR
2RT correct maximum  (2)

D 

L1

5.1.4

                ✔RT 
A =      2 158 000 000     × 100 %   ✔M
       3 441 000 000 000 
 = 0,062714327%  ✔CA 
 = 0,06%  ✔R 

AO 
1RT correct values 
1M multiply by 100 
1CA simplification 
1R rounding 
If omitted zeros =  max 3 marks  (4)

D 

L2

5.2.1

A person who is able and willing to work, but cannot find  work  ✔✔A
OR

2A explanation

D 

L1

Q

Solution

Explanation

T&L

People who are without work ✔✔A 
OR
People who are jobless ✔✔A 
OR
Not earning a salary / wage / income  ✔✔A 
OR
Retrenched ✔✔A

2A explanation (2)

5.2.2

X = 1 748 – 506  ✔M
 =1 242  ✔A 
OR
X = 16 172 – (1 391+ 806 + 4 991+ 2 513 + 1 417 + 321 +   999 + 2 492)  ✔M
= 1 242 ✔A 

1M subtracting correct values
1A simplification 
1M subtracting correct values
1A simplification 
No penalty for  including zeros  (2)

D 

L1

5.2.3

Questionnaire ✔✔A 
OR
Survey  ✔✔A 
OR
Population census ✔✔A 
OR 
Document analysis✔✔A 
OR
Interview  ✔✔A

2A correct answer  (2)

D 

L1

Q 

Solution

Explanation

T&L

5.2.4

Percentage of people
          ✔RT
1412 000  ×   100 %    ✔M 
4507 000          1 
= 31,329 %✔CA 

1RT using both correct values
1M percentage calculation
1CA simplification 
If omitted zeros   = full marks
NPR  (3) 

D 

L2

5.2.5

16 172 000 : 5 882 000   ✔RT 
2,7494 : 1  ✔A

1RT both correct values 
1A ratio in unit form 
Accept: 

• 2,749 / 2,75 / 2,7  (2)

D 

L2

5.2.6 

                                        ✔RT 
Probability (NEA) =    697 000    ✔RT
                                 1 893 000 
 = 0,368  ✔CA 
OR
Probability (NEA) =    697 000     ✔RT 
                               15 475 000 
 = 0,045  ✔CA 

AO 
2RT correct values 
1CA simplification 
OR
2RT correct values 
1CA simplification 
If omitted zeros = full marks 
NPR   (3)

P 

L2

Q 

Solution 

Explanation 

T&L

5.2.7

Do not mark this question.   

5.2.8

3 ✔✔A
9 ✔A 
= 31 ✔CA 

AO 
2A numerator 
1A denominator 
1CA simplification (4)

P 

L3

[35]

TOTAL: 150

QUESTION   5 

Mark out of 29 

Mark out of 35 

29 

35 

28 

34 

27 

33 

26 

31 

25 

30 

24 

29 

23 

28 

22 

27 

21 

25 

20 

24 

19 

23

18 

22

17 

21

16 

19

15 

18

14 

17

13 

16

12 

14

11 

13

QUESTION  5

Mark out of 29 

Mark out of 35

10 

12

9 

11

8 

10

7 

8

6 

7

5 

6

4 

5

3 

4

2 

2

1 

1