Symbol 

Explanation 

M 

Method 

MA 

Method with accuracy 

CA 

Consistent accuracy 

A 

Accuracy 

C 

Conversion 

S 

Simplification 

RT/RG/RM 

Reading from a table/Reading from a graph/Reading from a map 

F 

Choosing the correct formula 

SF 

Substitution in a formula 

J 

Justification 

P 

Penalty, e.g. for no units, incorrect rounding off etc. 

R 

Rounding Off/Reason 

AO 

Answer only 

NPR 

No penalty for rounding 

QUESTION 1 [22 MARKS] INTEGRATED QUESTION 

Question 

Solution 

Explanation/Marks  
AO: FULL MARKS 

Topic/L 

1.1 

1.1.1 

DM Row Travel Agency ✔✔ RT 

2 RT correct agency   (2) 

F  
L1 

1.1.2 

Reference Number: 0674582 ✔✔ RT 

2 RT correct Voucher no.   (2) 

F  
L1 

1.1.3 

3 nights ✔✔ RT 

2RT correct no of nights   (2) 

F  
L1 

1.1.4 

3 × R1 440,00 ✔ M  
= R4 320,00 ✔ CA 

1M×1 440,00  
1CA simplification (2) 

F  
L1 

1.2 

1.2.1 

250 + 330 + 450 + 500 + 1 000 + 1500 + 2 000 
= 5 580 mℓ ✔M  
5 580 = 5,58 ℓ ✔ CA
1000
OR  
0,25 + 0,33 + 0,45 + 0,5 + 1 + 1,5 + 2 l ✔MA 
= 5,58 l ✔CA 

1M addition all values  
1CA dividing and  simplifying   (2)

M  
L1 

1.2.2 

No. of A containers= 1 500 ✔M  = 6 ✔ CA 
                                   250

1M division correct values 
1CA No of A containers   (2) 

M  
L1 

1.3 

1.3.1 

42,2 km ✔✔ RT 

2 RT distance   (2) 

M&P  
L1 

1.3.2 

Difference in height above sea level  
= 46 – 35 ✔ RT  
=11 m ✔ CA 

1RT correct values  
1CA difference (2) 

M&P  
L1 

1.4 

1.4.1 

Mode = 61 ✔ RT  
 = 47 ✔

2RT mode   (2) 

D  
L1 

1.4.2 

Range = 86 – 18 ✔ MA  
= 68 ✔CA 

1MA subtracting correct  values  
1CA range (2)

D  
L1 

1.4.3 

Raw mark = 86 × 150 ✔ MA 
                   100
 = 129 ✔ CA  
OR  
Raw mark = 0,86 x 150 MA  
 = 129 ✔ CA 

1MA % of 150  
1CA raw mark   (2) 

D  
L1 

[22] 

QUESTION 2 [29 MARKS] FINANCE

Question 

Solution 

Explanation/Marks  
AO: FULL MARKS 

Topic /L 

2.1 

2.1.1 

Total amount = 1 200 × 60 ✔ M  
 = R72 000 ✔ CA 

1M multiplication  
1CA amount (2)

F  
L1 

2.1.2 

 30 × 20 000 = R6 000 ✔M ✔ CA  
100
OR  
School’s contribution = 0,3 x 20 000 ✔ M  
= R6 000 ✔ CA 

1M multiplication of correct  values  
1CA simplification (2) 

F  
L1 

 Ratio 2 000 : 20 000 ✔MA ✔A  
1 : 10 

1MA for ratio and 2000  
1A for 20 000 (2)

F  
L1 

2.1.4 

Balance = 2 000 – (10 × 50)
 = R1 500 ✔M  
1500 = 50 ✔M  
  30
Total T-Shirts = 50 + 10  
 = 60 ✔CA 

1M balance after sale of 10 T  shirts  
1M division  
1CA total number of T-shirts     (3) 

F  
L2 

2.2 

2.2.1 D = 24 901 – 23 901 ✔M  
 = 1000 kwh ✔A 

1M subtracting values  

1A simplifying (2) 

F  

L1 

2.2.2 

Costs = 100 × 132,70 + 50 × 155,30 ✔M  
= 13 270 + 7 765  
 = 21 035 ✔M  
= 21035 ✔CA
     100
= R210,35 

1M multiplication and  

addition  

1M simplification  

1CA dividing by 100  

 (3) 

F  

L2 

2.2.3 

VAT amount=   15   × 210,35 ✔M  
                       100
 = R31,55 ✔A  

1M multiplication of 15% by  210,35  

1A simplification (2) 

F  

L1 

2.3 

Inflation is the increase in price of goods and  services e.g. the price of petrol increases with  time. ✔✔ O 

2 Explanation   (2) 

F  

L1 

2.3.2 

Price increase = 16,21 – 16,02 ✔M  
 = 19c OR R0,19 ✔A 

1M subtraction of values  1A difference (with units cents  or Rands) (2)

F  

L1 

2.3.3 

Distance = 5 × 50 × 2 = 500 km ✔M 
Fuel used = 500 ✔M =  40 ݈݅Litres ✔CA  
Increase in fuel cost= 40 × 0,19 = R7,60 ✔CA  
OR  
Distance = 50 x 2 ✔ = 100 km for a day  
Fuel used = 100 = 8 ℓ ✔ 
                   12,5
Increase in cost of fuel for 1 day = 8 x 0,19   = R1,52 ✔
Increase in cost of fuel for 5 days = R1,52 x 5 ✔  = R7,60 ✔ 
OR  
2 x 50 x 5 = 500 km ✔ 
Petrol used = 500 = 40 ℓ ✔ 
                      12,5
Cost of fuel after increase = 40 x 16,21 = R648,40 ✔
Cost of fuel before increase = 40 x 16,02 = R640,80 ✔
Increase = R648,40 – R640,80 = R7,60 ✔

1CA from 2.3.2  
1M distance for a day (50 × 2)
1M distance for 5 days  
1M division by 12,5  
1CA simplification  
1CA increase   (5) 

F  

L3 

2.4 

2.4.1 Balance = R13 502,64 ✔✔RT 

2 RT   (2) 

F  

L1 

2.4.2 

Fee = 42,37+17,47+100,88 = R160,72 ✔ RT✔CA 

1 RT adding correct values 
1 CA simplification   (2) 

F  

L1 

[29]

QUESTION 3 [20 MARKS] MEASUREMENT 

Ques. 

Solution 

Explanation/Marks  AO: FULL MARKS 

Level 

3.1.1 

Total distance = 6,3 + 13,02 + 5,04  ✔M 
 = 24,36 km ✔CA 

1M Addition of correct  values  
1CA Simplification (2) 

M  
L1 

3.1.2 

Perimeter = 120 × 2 + 90 × 2   ✔M 
 = 420 m (or 0,42 km) ✔A 

1M distance around 
1A simplification   (2)

M  
L1 

3.1.3 

No of rounds = 1,6 km  ✔RT ✔M   
                         420 m
= 1600 ✔C
    420
 = 3,81 ✔CA  
Completed rounds =3 ✔R 

1 RT value of 1,6 km 
1 M Division  
1 C Conversion  
1 CA simplification 
1 Rounding to completed  rounds   (5)

M  
L2 

3.1.4 

: Goal(%) =   steps run  × 100%
                   Target steps
 = 5859 × 100%✔M  
    6000
 = 97,65%✔CA 

1M substitution  
1CA simplification  
(NPR)   (2)

M  
L2 

3.1.5 

Distance = 5,04 × 1000 ✔M  
                          756
 = 0,6665 ✔CA  
 = 0,67m ✔CA 

1M conversion to m 
1M division  
1CA simplification  
1CA rounding (4) 

M  
L2 

3.2.1 

V = πr²h   ✔M  
 V = 3,142 × 2.5² × 12,75  
 = 250,38 cm³ ✔CA 

1M substituting radius 
1M substituting height 
1CA simplification  
(NPR) (2) 

M  
L2 

3.2.2 

100 mℓ : 211 KJ ✔M 
250,38 : ?  
? = 211 × 250,38 ✔M = 528,30 KJ✔CA 
             100

1Mconcept of ratio  
1M method  multiplication of correct  values and dividing by  100 
1CA simplification (3) 

M  
L2 

[20]

QUESTION 4 [11 MARKS] MAPS AND REPRESENTATIONS 

Ques. 

Solution 

Explanation/Marks  AO: FULL MARKS 

Level 

4.1 

South ✔✔RT 

2RT correct direction   (2)

M&p  
 L1 

4.2 

✔RT  
2,5 cm : 20 km  
1.6 : 10 × 1000 × 100
1 : 20 × 1000 × 100
               2,5
 1 : 800 000 ✔CA  
OR  
2,5 cm : 20 km  
1 cm : 8 km x 1000 000  
1 : 800 000 

1RT measuring scale 
1M conversion from  km to cm  

1CA expressing in  unit ratio    

 (3)

M &p 
 L2 

4.3 

2,5 cm : 20 km  
6,5 cm : ? (distance from Queenstown CBD and Whittesea)✔M 
distance =   20 × 6,5 ✔M  
                       2,5
 =  52 km ✔CA  
OR  
1 : 800 000 (CA from 4.2) 
6,5 : 800 000 ×  6,5cm ✔M✔M  
Distance =  800 000 × 6,5 
                    1000 × 100
 = 52 km ✔CA  
(Accept 6,2 – 6,7 cm)  
(Accept 49,6 – 53,6 km) 

1CA from 4.2  
1M measuring  distance on map  
1M multiplication of  values  
1M division by 2,5 
1CA simplification (4)    

1M measuring  
distance on map  
1M multiplication  
1M conversion to km 
1CA simplification     (4)

M &p 
 L2 

4.4 

Numeric scale ✔✔ A  
Representative scale / Ratio scale ✔✔A  
Verbal scale / Word scale ✔✔A 

2A Correct scale   (2)

M &p 
L1 

[11]

QUESTION 5 [18 MARKS] DATA HANDLING 

Ques. 

Solution 

Explanation/Marks  AO: FULL MARKS 

Level 

5.1 

Gauteng ✔✔RT 

2RT correct province   (2)

D  

 L1 

5.2 

1 145 861; 2 745 590; 3 509 953; 4 039 939; 5 404 868;  5 822 734; 6 562 053; 10 267 300; 12 272 263 ✔✔RT 

2RT arranging all  values starting with  smallest.   (2) 

D  

 L1 

5.3 

Limpopo ✔✔RT 

2RT middle position  CA from 5.2 and  check province (2) 

D  

 L1 

5.4 

5.4.1 Free State and North West ✔✔CA 

CA from 5.2  1 mark for each  province (2) 

D  

 L1 

5.4.2 Eastern Cape and KwaZulu-Natal ✔✔CA 

CA from 5.2  1 mark for each  province (2) 

D  

 L1 

5.5 

IQR represents 50% ✔✔A 

2A   (2) 

D  

 L1 

5.6 

No. of listeners in NW =    90   ×  3 509 953✔M  
                                        100
= 3 158 957,7✔1S  
 = 3 158 958✔CA 

1M 90 % of the  population  
1S simplification  
1CA (Rounded to the  nearest whole number  people cannot be decimals)   (3) 

D  

 L2 

5.7 

% Mean =   95 + 87 + 91 + 96 + 91 + 88 + 80 + 90 + 90 ✔M  
                                                  9
 = 808 ✔M  
      9
= 89,78% ✔CA 

1M adding the  percentages  
1M dividing by 9  
1CA simplification  
(NPR)   (3) 

D  

 L2 

[18]

TOTAL:

100