SYMBOL 

EXPLANATION 

M 

Method 

MA 

Method with accuracy 

CA 

Consistent accuracy 

A 

Accuracy 

C 

Conversion 

S 

Simplification 

RT/RG/RM 

Reading from a table OR reading from a graph OR diagram OR from map a OR a  plan 

F 

Choosing the correct formula 

SF 

Substitution in a formula 

J 

Justification 

P 

Penalty, e.g. for no units, incorrect rounding off etc. 

R 

Rounding Off/Reason 

AO 

Answer only 

NPR 

No penalty for rounding 

O 

Opinion 

D 

Define 

QUESTION 1 [23 MARKS] 

Ques. 

Solution 

Explanation 

Level 

1.1.1 

Amount overdue  
= R26 263,55 – ✔M R25 754,61 ✔RT  
= R508,94  

OR  

Amount overdue  
= R2 696,94 – ✔M R2 188,00 ✔RT  
= R508,94 

1 RT Correct values 
1M Subtracting  

OR  

1 RT Correct values 
1M Subtracting  (2)

L2  

F 

1.1.2 

Probability  
= 2 ✔ A
  11 ✔ A    
= 0,18 ✔ CA 

1A Numerator  
1A Denominator  
1CA Rounding (3) 

L2  

P 

1.1.3 

EBUS 2715 fees  
= 2 696,94 + (3 715 × 7) + (4 280 × 2) + 3 510  + 1 020 + 25,21 + 14,40 + 210 – 2 188 ✔RT✔ M✔M 
= 39 853,55  
= 45 198,55 – 39 853,55 ✔M  
= R5 345  
Difference = 5 345 – 3 715  
 = R1 630 ✔CA  
Statement is not valid ✔O 

1 RT All correct values 
1M Adding values  
1M Subtracting 2188 
1M Subtracting from  45 198,55  
1 CA Difference  
1O Not valid  (6)

L4  

F 

1.1.4 

% Registration fee = 1020  ✔ RT x 100 ✔M  
                                  25 754,61
= 3,96%✔CA OR 4% 

1RT Correct values  
1M Multiplying by 100 
1CA Percentage  
NPR (3)

L2  

F 

1.2.1 

Semester 1 = ( 3 715 x 4) + 4280 + 5345   ✔M 
                                          6  ✔M
= R4 080,83 ✔CA  
Semester 2 = ( 3 715 x 3) + 3510 +  4280    ✔M  
                                                5
 = R3 787 ✔ CA  
Difference = R4 080,83 – R3 787 ✔M  
 = R293,83 ✔CA 

CA from 1.1.3  
1M Adding all values 
1M Dividing by 6  
1CA Mean  
1CA Mean semester 2 
1M Subtract  
1CA Difference  (6)

L3  

D 

1.2.2 

Amount for 2017 = 4280 × 100 ✔M✔M 
                                           105
 = R4 076,19 ✔CA  
OR  
Amount for 2017 = 4280 ✔M✔M 
                               1,05
 = R4 076,19 ✔CA

1M Multiplying by 100 
1M Dividing by 105 
1CA Amount  
OR  
2M Dividing by 1,05 
1CA Amount (3) 

L2  

F 

[23]

QUESTION 2 [29 MARKS] 

Ques. 

Solution 

Explanation 

Level 

2.1.1 

Distance from Vanrhynsdorp to Garies  
 = 433 – 289 ✔RT OR = 258 – 114 ✔RT 
= 144 km ✔A OR = 144 km ✔A
Distance from Kamieskroon to Springbok  
= 547 – 479 OR = 68 – 0  
= 68 km ✔A OR = 68 km  
Incorrect ✔O  
Strip chart not drawn to scale ✔R 

1 RT Correct values 
1A Distance  
1A Distance  
1O Incorrect  
1O Reason  (5) 

L4  

M&P 

2.1.2 

Distance = (289 – 52) + 121 ✔M  
 = 358 km ✔CA  
OR  
Distance = 65 + 44 + 53 + 75 + 121 ✔M  
 = 358 km ✔CA  
Distance = Speed × Time  
 358 =  95 ×  Time ✔SF  
358 = Time ✔M  
 95
Time = 3,76842 hours  
Minutes = 0,76842 × 60  
 = 46 minutes ✔C  
Time of arrival = 7:00 + 0:45 + 3:46 ✔M  
 = 11:31 ✔CA 

1M Add correct  distances  
1CA Distance  
1SF Substitution  
1M Change subject of  formula  
1C Convert to minutes 
1M Adding times  
1CA Time  (7) 

L2  

M&P  

L3  

M 

2.2.1 

Area of rectangle = length x width  
 = 150 × 120 ✔C✔SF  
 = 18 000 mm² ✔A 
Area of a circle =  π ×  radius ×  radius 
 = 3,142 × 40 mm ×  40 mm ✔A 
= 5 027,2 mm² ✔CA  
Area without the photo = 18 000 – 5 027,2 ✔M  
= 12 972,8 mm2 ✔CA

1C Convert to mm 
1SF Substitution  
1A Area of rectangle 
1A Radius  
1CA Area of circle 
1M Subtraction of the  two areas  
1CA Area without a  photo  (7)

L3  

M 

2.2.2 

Surface area  

= 2(length ൈ width + width ൈ height + length ൈ height)  = 2(390 ൈ 270 + 270 ൈ 300 +390 ൈ 300)✔SF✔A  = 2(105 300 + 81 000 + 117 000) S✔ 

= 606 600 cm2 ✔CA 

1SF Substitution  
1A Correct values  
1S Simplification  
1CA Surface area.   (4)

L3  

M 

2.3 

Company A  
IQR = 3 500 – 1 400 ✔RT   = 2 100 ✔CA  
Range = 5 300 – 800   = 4 500 ✔A  
Company C  
IQR = 5 800 – 3 900   =1 900 ✔CA  
Range = 6 300 – 2 800   = 3 500 ✔CA  
Both IQR and range are higher for Company A than  Company C ✔O  

OR  
Both IQR and range are smaller for company C than  Company A ✔O 

1RT Correct values 
1CA IQR (A)  
1A Range (A)  

1CA IQR (C)  
1CA Range (C)  
1O Finding    

(6)

L3  

Data 

[29]

QUESTION 3 [18 MARKS]

Ques. 

Solution 

Explanation 

Level 

3.1.1 

Value of A = 6 × 3 + 1 × 6 ✔M  
= 18 + 6  
 = 24 ✔A  
Value of B = 19 – 4  
 = 15 ✔M  
     3
 = 5 ✔A 

1MA Matches won and drawn 
1A Value of A  
1M Subtracting and dividing by 3 
1A Value of B  (4) 

L2  

D 

3.1.2 

Probability =  1  ✔A✔A 
                     14

CA from 3.1.1  
1A Numerator  
1A Denominator   (2) 

L2  

P 

3.1.3 

Points = 2 × 3 + 1  
 =7 ✔A  
Total = 21 + 7  
 = 28 ✔MA  
Difference = 28 – 24  
 = 4 ✔MA  
Statement not valid ✔O 

CA from 3.1.1  
1A Points  
1MA Total points  
1MA Difference  
1O Not valid (4) 

L4  

D 

3.2.1 

School A = 45 × 2 × 3 = 270 ✔M
45 × 2 = 90  
Total = 270 + 90  
 = 360 minutes ✔MA  
Hours = 360
               60
 = 6 h ✔C  
School B = 30 ×  8 + 30  
 = 240 + 30  
 = 270 minutes  
Hours = 270
               60
 = 4,5 h ✔CA  
School B is CAPS compliant ✔O 

1M No. of minutes  
1M Total no. of minutes  
1C Convert to hours  
1CA No of hours for school B 
1O Conclusion  (5)

L4  

M 

3.2.2 

Ratio = 62 ✔MA 
             2
 = 31  
Grade 10 = 31 × 4  
 = 124   ✔MA 
Grade 11  
= 31 × 3  
= 93  
Total books = 62 + 124 + 93  
 = 279 ✔CA 

1MA Concept of ratio  
1MA Total for Grade 10 and  Grade 11  
1CA Total  (3)

L3  

D 

[18]

QUESTION 4 [30 MARKS] 

Ques. 

Solution 

Explanation 

Level 

4.1.1 

There are emergency exit points between row 8  and row 9 ✔✔A 

2A Reason (2) 

L4  

M&P 

4.1.2 

Seats in the economy class  
= 18 ✔MA ×  6 ✔MA  
= 108 ✔A 

1MA Seats per row  
1MA Total rows  
1A Total no of seats   (3)

L2  

M&P 

4.1.3 

There is more space ✔✔R  
OR  
Service is better ✔✔R  
OR  
It is more relaxing ✔✔R  
Any other relevant reason. 

2R Reason  (2)

L4  

M&P 

4.2.1 

Quarter finals = (1 412  × 2) + (4 249  × 2) ✔RT  
= 2 824 + 8 498 ✔MA  
 = $11 322 ✔CA  
Finals = (2 186  × 2) + (5 538 × 2) ✔MA  
= 4 372 + 11 076  
 = $15 448 ✔CA  
Total amount = 11 322 +15 448 ✔M  
 = $26 770 ✔CA  
Statement is valid ✔O 

1RT Correct values for  both matches × 2  
1MA Adding  
1CA Total  
1RT Correct values for  both matches × 2
1CA Total for final  
1M Adding  
1CA Total in dollars 
1O Valid  (8) 

L4  

F 

4.2.2 

% change = 5538 - 3918 × 100% ✔RT✔M✔M  
                        3918
 = 41,35% ✔CA  
OR  
% change = 4295 - 1995 × 100% ✔RT✔M✔M  
                         1995
 = 115,29% ✔CA

1RT Correct values  
1M Correct  denominator  
1M Multiplying by 100 
1CA Percentage   (4) 

L2  

F 

4.2.3 

Year 1 = 20 000 × 1,065 ✔M  
 = $21 300 ✔CA  
Year 2 = 21 300 × 1,065  
 = $22 684,50 ✔CA  
Rate for 9 months = 9 × 6,5%  
                               12
 = 4,875% ✔A  
Year 3 = 22 684,50 × 1,04875  
 = $23 790,37 ✔CA  
OR  
Final amount  
= 20 000 × 1,065 ✔M × 1,065 ✔M  × 1,04875✔A✔A  
= $23, 79037 ✔CA 

1M Increasing by 6,5% 
1CA Amount for  year 1
1CA Amount for  year 2
1A Interest rate for  9 months 
1CA Final amount  (5) 

L3  

F 

4.2.4 

Men play more vigourously ✔✔R  
OR  
Men’s matches attract more spectators ✔✔R 
OR  
Performance/Skills better ✔✔R  
Any other relevant reason 

2R Reason  (2) 

L4  

F 

4.2.5 

Ticket prices increase from day 1 to the final  day ✔✔O  
Competition gets tougher and therefore matches  become more interesting to watch. ✔✔R 

2O Trend  
2R Reason for  trend  (4) 

L4  

D 

[30] 

TOTAL:

100