QUESTION 1
| 1.1 | a = −4,1536 b = 0,9580 y = −4,1536 + 0,9580x penalty for rounding | ✓a = −4,1536 ✓b = 0,958 ✓y = −4,1536 + 0,958x (3) |
| 1.5 | x̄ = 60,8 Standard deviation = 17,51 (60,8 − 17,51 ; 60,8 + 17,51) (43,29; 78,31) 6 learners (Accept) | ✓ Standard deviation=17,51 ✓(43,29; 78,31) ✓6 learners (3) |
QUESTION 2
| 2.4 | Award 1 mark for Min. and Max and 1 mark for Q3 | ✓Min and Max ✓Q3 (2) |
QUESTION 3
| 3.6 | Alternatives: PR = √50 ✓✓ sin θ = 2√10 ✓✓ θ = 63,43°✓ √50 OR PR = √50 ✓ PQ = √10 ✓ cos θ = √10 ✓✓ θ = 63,43° ✓ √50 OR PR = √10 ✓✓ tan θ = 2√10 ✓✓ θ = 63,43° ✓ √50 | (5) |
QUESTION 4
| The diagram shifted and some dimensions were not accurate. This caused the question to be opened for different answers when using different methods especially in 4.3 to 4.6. There is, however, an easy fix.: |
| 4.1 | x2 − 6x − y2 − 4y + 9 = 0 x2 − 6x + 9 + y2 − 4y + 4 = −9 + 9 + 4 (x −3)2 + (y −2)2 = 4 C(3;2) and r = 2 Answer Only: Full Marks | ✓ completing square |
| 4.4 | 4.4 alternatives / alternatiewe: Solve/ Los op y=-2x+2 and y=1/2 x+1/2 simultaneously to yield x=0,6 y=0,8 OR / OF | ✓ length of TA |
| 4.6 | Alternative: TAC = 90°✓ tan ACT = 2✓ ACT = 63,43✓ BCA = 126,86°✓ | (4) |
QUESTION 5
| 5.2 | A common error is to divide by sin P. Awarded max of 2/4 if solved cos P =0,5 correctly. | (4) |
QUESTION 10
| 10.2.4 Common alternative ∴RQ/RS = RP/BR ✓S ∴ BR . RQ = RS . RP |