Symbol

Explanation

M

Method

MA

Method with accuracy

CA

Consistent accuracy

A

Accuracy

C

Conversion

S

Simplification

RT/RG/RM

Reading from a table/Reading from a graph/Reading from a map

F

Choosing the correct formula

SF

Substitution in a formula

J

Justification

P

Penalty, e.g., for no units, incorrect rounding off etc.

R

Rounding Off/Reason

AO

Answer only

NPR

No penalty for rounding

QUESTION 1 [30 MARKS]

Ques

Solution

Explanation AO: FULL MARKS

T&L

1.1.1

Deposit as % of lay-bye price = 1200 × 100%  M
                                                   4800
= 25% CA

1M percentage calculation
1CA answer   (2)

F L1

1.1.2

Months = 3 600   A     
                  400    M
= 9 months CA

1A identifying use of R3 600
1M divide by 400
1CA number of months  (3)

F L1

1.1.3

Balance          = R3 600 – (R400 × 7) M
= R800,00 CA

OR

Balance of months = 2
Amount   = 2 × 400      M
= R800 A

1M for subtracting 7 instalments from R3 600
1CA answer 1M method for multiplying 2 months by instalments
1A answer (2)

F L1

1.2.1

Cost price = R60 + R45 + R5 M
= R110 A

1M adding correct values
1A answer  (2)

F L1

1.2.2

Profit = R176 – R110 M
= R66,00 A

1M subtracting cost price from selling price
1A correct amount   (2)

F L1

1.2.3

                                           RT
Income (Rands) = R176n, where n stands for the number of t-shirts sold.

2RT for the R176n  (2)

F L1

1.2.4

Cash discount = 15 × 176     MA
                         100      1
= R26,40     S
= R27,00 OR R26,00     R

1MA discounted percentage calculation
1S simplification
1R rounding to the nearest Rand.    (3)

F L1

Ques

Solution

Explanation

T&L

Cost of a dozen = 110 × 12    MA
                              60
= R22,00 A

OR

Dozens = 60
                12
= 5    M
Cost price of a dozen = 110
                                        5
= R22 MA

1MA cost of a dozen answer  (2)

Profit = R125 – R110
= R15        M
Average profit per egg = R15    M
                                        60
= R0,25    A

1M average calculation
15
60
1A answer
(Accept 25 cents).     (3)

F
L1

1.4.1

Total population in 2001(44 819 778): A
Forty-four million, eight hundred and nineteen thousand seven hundred and seventy-eight.

2A correct value in words  (2)

D L1

1.4.2

Increase in total population = 51 770 560 – 40 583 573M
= 11 186 987 CA

1M subtraction correct values
1CA answer (2)

D L1

1.4.3

Difference in population between KZN and NC in 1996  
                        RT
= 8 572 302 - 1 011 864     M
= 7 560 438 CA

1RT correct values
1M subtraction
1CA difference  (3)

D L1

1.4.4

Northern Cape RT

2RT correct province (2)

D L1

[30]

QUESTION 2 [31 MARKS] FINANCE

Ques

Solution

Explanation/Marks AO: FULL MARKS

T/L

2.1.1

Amoti: Dan = 3 :  5                         [8 shares]
Dan invested = ³/₈ × 16 000   MA
= R6 000    CA

1MA ³/₈ of the investment.
1CA Dan’s amount  (2)

F
L2

2.1.2

Dan’s share of profit = ³/₈  × 2 880     M
= R1 080,00   CA

1M fraction of the profit
1CA Simplification Dan’s share of profit  (2)

F L1

Amoti's interest: R2880 – R1080
= R1800    MA
Mary's interest:
1st year = 108,5 × 10 000        = R10 850,00 MA
                  100
2nd year = 108,5 × 10 850       = R11 772,25 MA
                   100
Total interest in 2 years
= R11 772,25 – 10 000 M
= R1 772,25    CA
Amoti had better investment by R27,75. J

OR

Amoti’s investment = 16 000 × 5
                                       8
= R10 000   A
                                              M
Return on investment = 1 800 × 100%
                                     10 000
Interest in 2 years      = 18%    S
Mary’s return in two years =[ (1,085 × 1,085) – 1]×100
= 17,7225%    M
Difference is 18% – 17,7225% = 0,2775%    A 
Earnings in favour of Amoti          J

1MA Mary’s amount at end of 1st year.
1MA Mary’s amount in 2nd year
1M subtracting from R10 000
1CA interest
1J better in favour of Amoti

OR

1A investment amount
1M return on interest in 2 years R1 800
1S simplification for interest in 2 years for Amoti
1M interest rate in 2 years
1A difference in interest amounts.
1J Amoti had better investment (6)

F

L4

Ques

Solution

Explanation

T&L

2.2.1

R147,74      RT

2RT correct amount (2)

F
L1

2.2.2

Block 1:  Cost 550 × 124,49 = 68 469,5 cents  M
= R 684,70    C
Block 2: Cost 140 × 141,43 = 19 800,2cents
= R198,00         A
Total Cost = R684,70 + R198,00 + R147,74 + 435,24 M
= R1 465,68 CA

1M cost of 550 kWh
1C conversion cents to Rands
1A cost of 140 kWh
1M adding the values
1CA total answer   (5)

F
L3

2.2.3

VAT amount included = 15 × 𝑅1 465,68 M
                                    115
= R191,18    CA

OR

VAT exclusive amount = R1 465,68 ÷ 1,15 M
= R1 274,50 CA

VAT amount = R1 465,68 – R1 274,50
= R191,18     CA

CA from 2.2.2
1M for the fraction
1M multiplication
1CA simplification and Ans. (concept of money)
1M dividing by 1,15
1CA VAT exclusive amount
1CA VAT amount   (3)

F
L2

2.3.1

12 Months      RT

2RT correct months (2)

F
L1

= R646 462 M
Total expenses = 114 859 + 123 567 + 14 600 + 23 982 + 3 679 + 1 650 + 1 080 + 146 912 + 17 244 + 43 432 + 12 456 + 23 678      M
= R527 139 CA

Difference = Income ─ Expenses
= R646 462 ─ R527 139 M
= R119 323 CA
It is a surplus       J

1M finding total income
1M addition
1CA total expenses
1M subtraction
1CA difference
J justification   (6)

F
L3

2.3.3

Monthly charges = 1080RT M
                                12
= R90 CA

1RT yearly charges
1M divide by 12
1CA monthly charge (3)

F
L2

[31]

QUESTION 3 [29 MARKS]

Ques

Solution

Explanation

T&L

3.1

Gold  RT

2RT correct mineral (2)

D L1

3.2

Median (Total sales): 
13,3 ; 22,8 ; 47,6 ; 71,4 ; 72,6 ; 124,6 ; 139,3
= R71,4 billion rand A

OR

= 71 400 000 000

1M arranging in order
1A middle value
1A answer in actual value format  (3)

D L2

3.3

Q1 = 22,8 M
Q2 = 71,4
Q3 = 124,6 M
IQR = 124,6 – 22,8     M
= 101,8 billion rand S
Therefore, IQR is greater than 101 billion J

1M for Q1
1M for Q3
1M subtraction Q3 – Q1
1S simplification
1J answer   (5)

D
L3

= 417 232 ¸ 7 M
= 59 604,57 S
= 60 000 R

1M adding all values
1M total divide by 7/concept of mean
1S simplification
1R rounding  (4)

D
L2

3.5

Modal value = 2,1 billion M
= 2 100 000 000  CA

1M value of modal value
1CA value in number format (2)

D L2

Ques

Solution

Explanation

T&L

3.6

802 000 000 + 362 000 000 + 2 100 000 000 + 288 000 000 + 1 120 000 000 + 2 100 000 000
= 6 772 000 000 M
= ^{288 000 000}/_{6 772 000 000} ×  100%  M
= 4,25% CA

OR

0,802 + 0,362 + 2,1 + 0,288 + 1,12 + 2,1
= 6,772 billion MA
% for Gold = 0,288 × 100% M
                     6,772
= 4,25% A

1M percentage calculation
1CA correct %
1MA finding total royalties
1M percentage calculation
1A correct %

D
L2

3.7

P = 3 ×100%        A               M

7

= 42,86%                            CA

1A numerator
1M percentage calculation 1CA %
NPR

(3)

P L2

3.8

First 2 minerals/metals correctly plotted; 1CA
Any other 2 minerals correctly plotted:    1CA
Any other 2 minerals correctly plotted:    1CA
Joining the points:                                   1CA 

D L2

                                               RT
Difference = 70,5 million tons – 101,3 tons
= 70 500 000 – 101,3 M
= 70 499 898,7 tons    CA

1RT correct values
1M subtraction of correct values
1CA difference

QUESTION 4:[32 MARKS] FINANCE

Ques.

Solution

Explanation/Marks

T&L

4.1.1

Option 1: B RT
Option 2: A RT

OR

A: Option 2 RT
B: Option 1 RT

1RT correct option
1RT correct option  (2)

F L2

4.1.2

Breakeven point is where the income under option 1 is equal to the income under option 2.   A

2A explanation  (2)

F
L1

4.1.3

Use of calculations
Option 1:
Income = R20 × 12 SF
= R240 S

Option 2.
Income = R200 + (10 × 12) SF
= R320 S

Difference = R320 – R240 = R80 MA
Statement was correct he would have earned less R80          J

OR   

From Graph
Option 1
Income = R240    RT

Option 2
Income = R320 RT
Difference = R320 – R240 = R80 CA
Statement was correct he would have earned less R80 J

1SF substitution in formula
1S value for income for the day under option 1

1SF substitution in formula
1S value for income for the day under option 2

1MA finding the difference
1J Justification
2RT value of income form graph option1
2RT value of income form graph option 2
1CA finding the difference
1J Justification  (6)

F
L4

Ques,

Solution

Explanation/Marks

T&L

4.2.1

Average Inflation rate because it involves an increase of different goods over a period of time. O

2O Reasoning (2)

F L1

4.2.2

                                                            RT
Inflation rate decreased from 2016 to 2017 and prices of goods increased at a lower rate. O
                                                           RT
Inflation rate increased from 2017 to 2019 and prices of goods increased at a higher rate. O

1RT rate decreased from 2016 to 2017 1O prices of goods increase at lower rate
1RT rate increased from 2017 to 2019 1O prices of goods increases slightly faster  (4)

F L4

4.2.3

New price = old price × (100% + Inflation rate%)
                                            SF
R5356 = price in 2017 × (100% + 5,94%)
Price in 2017 =   5356     M
                          1.0594
= R 5 055,69 S
                                           SF
Price in 2019 = 5356 × (100% + 8,63%)
= R5 818,22 S
Difference = R5 818,22 – R5 055,69 M
= R762,53 CA

1M changing subject of the formula
1S simplification

1SF substitution
1S simplification
1M subtraction
1CA answer    (7)

F L3

Ques.

Solution

Explanation/Marks

T&L

4.3.1

Nigeria RT

2RT correct answer (2)

D
L2

4.3.2

 RT               RT
Closest in May 2020 and March 2021

1RT correct month and year
1RT correct month and year   (2)

D
L2

4.3.3

1. Trend: Nigeria’s CPI increases steadily from CPI of about 12,2 in April 2020 to CPI of about 18,0 in March 2021.
2. Trend for South Africa: Decreased from March 2020 to May, remained steady to June 2020, and increased from June to July 2020.

2J increasing from April 2020 to May 2021.  (2)
1J decreasing from March to May
1J remaining steady May to June
1J increasing from June to July.  (3)

D
L4

D
L4

[32]

QUESTION 5: [28 MARKS]     FINANCE; DATA HANDLING AND PROBABILITY

Ques

Solution

Explanation

T&L

Basic annual salary = R27 678 × 12M
= R332 136 CA

Taxable Income = R332 136 – (7,5% of 332 136) M
= R332 136 – 24 910,20
= R307 225,80 S

Annual tax before rebates.
= 37 062 + 26% of taxable income above 205 900
= 37 062 + 26% × (307 225,80 – 205 900)      SF
= R63 406,50 or R63 406,71 CA

Annual tax after rebates = R63 406,50 ─ 14 958
= R48 448,50 MA

Monthly tax after rebates = 48 448,50 MA
                                                12
= R4 037,38

1CA annual salary
1M calculating income taxable.
1S simplification
1SF correct bracket
1CA annual tax
1MA finding tax after rebates
1MA finding monthly tax
NPR (8)

F
L3

5.1.2

Monthly pension = 24 910,20 ÷ 12
= R2 075,85 M
R27 678 ─ (4 037,38 + 2 075,85 + 106,00 + 585,64)
= R27 678 ─ (6 804,87) S
=R20 873,13    CA

1M monthly pension
1M subtraction of total deductions
1S simplification
1CA answer
NPR  (4)

F L2

Ques.

Solution

Explanation

T&L

5.2.1

Mary: age 16 years and BMI = 29 from graph gives 95% percentile
Jolly: age 18 years and BMI = 30 from graph gives about 93% percentile.  RT
Checking from the status: Mary is overweight  RT
Jolly is at risk of overweight.  RT Both wrong.  J

1RT reading from the growth chart
1RT reading from the growth chart
1RT reading status table
1RT reading from status table
1J justification.  (5)

D
L4

5.2.2

From the Growth chart:
19 years and 35% give BMI = 26    RT
Mary now at 16 years with at BMI = 29 She must lose = 29 – 26  M
= 3  CA

2RT using the 19 and 85% to get BMI = 26
1M subtracting 26 from 29
1CA answer. (4)

D
L4

5.3.1

Total  = 1 063 038 + 130 092 + 129 056 + 784 314
= 2 106 500  A

OR

Total = 757 105 + 1 349 395
= 2 106 500       A

1M adding all values
1A correct answer

1M adding all values
1A correct answer  (2)

D
L1

5.3.2

Probablity is the chances or likelihood of an event occurring.       A

2A explanation  (2)

P
L1

5.3.3

P(Black African with a degree) =   613 820   A
                                                    1 349 395  A
= 0,45  CA

1A numerator
1A denominator
1CA answer.
NPR    (3)

P
L2

[28]

TOTAL: 150