Symbol

Explanation

M

Method

M/A

Method with accuracy

MCA

Method with consistent accuracy

CA

Consistent accuracy

A

Accuracy

C

Conversion

S

Simplification

RT/RG/RM

Reading from a table OR Reading from a graph OR Read from map

F

Choosing the correct formula

SF

Substitution in a formula

J

Justification

P

Penalty, e.g. for no units, incorrect rounding off etc.

R

Rounding off OR Reason

AO

Answer only

NPR

No penalty for rounding

QUESTION 1 [20] 

Ques.

Solution

Explanation

Level

1.1.1

547 x 1 000 √
= 477 000 m √

1    MA correct values
1 correct answer  (2)

L1

M&P

1.1.2

N7 √
N14 √

1 A          (2)
1 A

L1

M&P

1.1.3

5 √√

2 A                (2)

L1  M&P

1.2.1

Distance around a figure √√

OR

Sum of the sides of a figure √ √

2 A correct definition  (2)

L1 M

1.2.2

9 + 13 +12 +14 √
= 48 cm √

1 MA adding correct values
1 correct answer  (2)

LI M

1.2.3

9 : 14 √√

1 A correct values
1 M as a ratio     (2)

L1
M

1.2.4

13 – 9 √
= 4 √

1 A correct values
1 M subtraction (2)

L1

M

1.3.1

42,2 x 100 000 √
= 4 220 000 cm √

1 C
1 correct answer (2)

L1
M

1.3.2

4,7 x 60 √
= 282 minutes √

1 M multiplying by 60
1 correct answer (2)

L1
M

1.3.3

0,75 x 42,2 √
= 31,65 √

1 MA multiplying
1 correct answer (2)

L1
M

QUESTION 2 [30]

Ques.

Solution

Explanation

Level

2.1.1

South West√√
North East √√A

2A First direction
2A Second direction  (4)

L2
M&P

2.1.2

Scale 15 cm√ = 200 km
Map distance =11,8 cm √ 
15 cm = 200 km
11,8 = 200 x 11,8 √
= 2 360 / 15
= 157,3 km √

1A Distance on map
1A Distance on scale
1M Multiplying by 200 and dividing by 15
1CA Actual distance in km   (4)

L3
M&P

2.1.3

Scale    15 cm : 200 km
15 cm : 20 000 000 cm √
1     : 1 333 333,333 √
1     : 1 000 000 √

CA from 2.1.2
1C mm to km
1S Simplification
1R Unit scale                (3)

L3
M&P

2.1.4

Japan was the host country √√

OR

The other countries were not the host countries √√A

2A Reason  (2)

L4
M&P

2.1.5

Russia √√

2 A correct country     (2)

L1
M&P

2.2.1

Clanwilliam and Citrusdal
= 214 -161        OR    386 -333 √
= 53 km                      = 53 km √
Piketburg and Malmesbury
=495 -430    OR       117 -52
= 65 km                     = 65 km √
Distance not equal √
Map not drawn to scale √

MA Subtracting correct values
1 CA Answer
1 CA Correct answer
1 Conclusion
1 Reason                        (5)

L4
M&P

2.2.2

From Vanrhynsdorp move south on the N7 √
Pass Clanwilliam and Citrusdal Turn left on R44 √
Pass Tulbagh and move forward till you reach Ceres √

3 A giving clear directions to Ceres (3)

L2
M&P

2.2.3

2/5 √√

1 A numerator
1 A denominator           (2)

L2
Prob

2.2.4

Distance = 495 km √
Speed    = 495 √
4,5 √
= 110 km /hr √
He is within the accepted speed limit √

1 A correct distance
1 C converting to hours 1CA speed
1 O                                 (5)

L4
M&P

QUESTION 3[26]

Ques.

Solution

Explanation

Level

3.1.1

30 000 litres = 30 000
                        1 000
= 30m3 √ C
Volume = π × radius × radius × depth
                    √C           √A
30 m³ = 3,142 × 2,4 m × 2,4 m × depth √ SF
30 m³ = 18,09792 × depth √ S
Depth = 30/18,09792
= 1,667 √CA
= 2 m √ R

1C Litres to m³
1C Cm to m
1A Radius
1SF Substitute correct values
1S Simplification
1CA Depth
1R Rounding            (7)

L3 M

3.1.2

10 000 litres = 40g
30 000 litres = 30 000 × 40 √MA
                       10 000
= 120 g per day √CA For March   
= 120 × 31 √MA
= 3 720 g
In kg      = 3 720
                1 000
= 3,72 kg √C
10 kg will be enough √O

1CA Grams
1MA Multiplying by 31
1C Convert to kg
1O Enough       (5)

L4
M

3.1.3

Diameter of fence = 4,8 m + 2 m + 2 m
= 8,8 m √A
Circumference of the fence = π x diameter
= 2 × 3,142 × 4,4 m √SF
= 27,6496 m √CA
Costs = 27,6496 m × 125
= R3 456,20 √CA

1A Diameter of fence
1SF Substitute correct values
1CA Circumference of fence
1CA Cost for labour   (4)

L3

M&F

3.2.1

10,4 inches √√RT

1RT value of length  (2)

L1 M

3.2.2

Area of A = length × width
= 10,4 inches × 18,796cm √RT
= (10,4 × 2,54) × 18,796 √C
= 26,416 × 18,796 √M
= 496,515136 cm² √CA
= 496,5 cm² √R

1C conversion
1M multiplication
1CA answer
1R rounding to 1 decimal digit    (5)

3.2.3

Perimeter = Length + width
     2
201,93 = 66,04 + width √SF
    2
100,965= 66,04 + width
100,965-66,04 = width √S
34,925 cm       = width √CA

1 SF substitution
1S simplification
1CA answer            (3)

L2 M

QUESTION 4 [24]

Ques.

Solution

Explanation

Level

4.1.1

24 √√RT

2RT     (2)

L1 M&P

4.1.2

P (No of 11B/Total =) ? √RT√
                                 ??
= ? √CA
  ??

1RT numerator
1RT denominator
1CA simplified answer (3)

L2 P

4.1.3

2 √√RT

2RT       (2)

L1  M&P

4.1.4

2/48 x 100 √
= 4,17% √√

1 A Correct values
1 M calculating percentage
1 CA rounded to two decimals     (3)

L2   M&P

4.2.1

Distance = Speed × Time
135 km = 98 km/h × Time √SF
Time = ????????
             ?????
= 135 √M
    98
= 1,37755102 h
                 √C                        √M
= 1h 23 minutes + 25 minutes
= 1h 48 minutes √CA

1M Changing subject of formula
1C Convert to min
1M Adding time
1CA Time taken                (5)

L3
M

4.2.2

Litres used = 135 √MA
                      12
= 11,25 litres √A
Petrol left = 50 litres – 11,25 litres
= 38,75 litres √CA
= 37,5 litres √MA Statement valid √O

1M Dividing by 12
1A No of litres
1CA No of litres left
1MA subtraction of full tank
1O Valid   (5)

L4 M

4.2.3

Distance = 135 x 2 √
= 270 km
Cost       = 270 x 1650 √
= 445 500
=445 500/ 100 √
= R4 455 √

1 M multiplying by 2
1 M multiplying by cents
1 C converting to rands
1 CA answer  (4)

L2
M&P

TOTAL:

100