MATHEMATICAL LITERACY PAPER 1
GRADE 12
MEMORANDUM
NATIONAL SENIOR CERTIFICATE
JUNE 2017

This memorandum consists of 6 pages.

Symbol  Explanation 
 M  Method
 CA  Consistent accuracy
 A  Accuracy
 S  Simplification
 RT/RG/RM  Reading from a table/Reading from a graph/Read from map
SF Substitution in a formula
P Penalty, e.g. for no units, incorrect rounding off etc.
R Rounding Off/Reason


QUESTION 1 [28 Marks]

Quest  Solution  Explanation  Marks 
1.1.1   p.a. means per annum ✓✓ OR
annual earning
R  (2)
1.1.2  One million, two hundred eighty five thousand, four hundred and fifty six ✓✓ (2) 
 1.1.3  1 285 500 ✓✓  Rounding (2)
 1.2.1  Price of an egg =17,9912 = 1,499 ✓
= R1,50 ✓
1A for 12
1CA (2 dp. money)
(2)
1.2.2  VAT = 14    ×59,88 ✓ = R8,38 ✓
          100
1M Multiplication
1A (2 dp. for money)
(2)
1.2.3  2,5 × 1 000 = 2 500 g ✓✓ 1MA Multiplication
1A
(2)
1.2.4  10 ?ℓ→8? 150 ?ℓ→?
? = 150 × 8  =120 ? ✓✓✓
          10 
2M
1A
(2)
1.3 Juice: Water = 1 : 5
10: ??
?? = 10 × 5  =50 glasses of water ✓
           1
1M
1A
(2)
1.4 Length = 0,294 ✓= 29,4 cm ✓
                0,01
1M division
1A
(2)
1.5.1 Number of boys = 9 – 3
= 6
1MA
1A
(2)
1.5.2 Range = 13 – 3 ✓ = 10  1MA 1A (2)
1.6.1 Learners that took part in research = 32 ✓✓ 2 RG (2)
1.6.2 Formal dress code ✓✓ 2 RG (2)
1.6.3 Boys that preferred traditional dress code =
24 – 16 ✓= 8 ✓
OR counting from graph – 8 boys ✓✓
1M subtraction of the values
1CA
AO
(2)

[28]

QUESTION 2 [26 Marks]

Quest.  Solution  Explanation  Marks 
2.1.1 Profit for 2015 = Income – expenditure
= 262 600 – 188 560 ✓
= 74 040 ✓
1MA subtraction
1A
(2)
2.1.2 Total expenditure in 2016 =
160 400 + 7 400 + 2 600 +10 400 + 360 + 7 200 +1 600 + 2 440 = 192 400 ✓
OR
Total expenditure = Income – profit
= 318 860−126 460 ✓
= 192 400 ✓
1M addition of expenses
1A
1M addition of expenses
1A
(2)
2.1.3  Depreciation increased by 50% ✓✓ 2RT (2)
2.1.4  % ???????? ?? ????????= ???????? ?? ???????? ×100
                                        ???????? ?? 2015
= 160 400−160 000 ×100 ✓
          160 000
=     400     ×100 = 0,25% ✓
   160 000
1SF
1A
(2)
2.2.1  Minutes (time) ✓✓  2RT  (2)
2.2.2    GRAPH SHOWING CELLEPHONE DEALS OPTIONS: A; B; C
2.22

Point (0; 500), another point on line cost = 500 ✓ line cost = 500 ✓
 (3)
2.2.3 Same cost for all the options. ✓✓ OR
None is cheaper. ✓✓
2RG (2)
2.2.4 P(C) =
           3 ✓✓

1 numerator
1 denominator
(Answer only full marks)
(2)
2.3.1 Cost of paraffin = 5,60 × 3 ✓= R16,80 ✓ 1MA Multiplication
1A
(2)
2.3.2 P = 5,60 ×1,1 ✓✓=R6,16 ✓
OR
P = 5,60 × 110 ✓✓= R6,16 
                 100
OR
Increase = 5,60 × 10% = R0,56 ✓
P = 5,60 + 0,56 ✓ = R6,16 ✓
2 MA Multiplication
1A
1MA for the increase
1M addition
1A
(3)
2.3.3 No. of tanks = 30 =15 ✓
                        2
Cost = 15 × 3 × 6,16 ✓= R277,20 ✓

1A for 15
1M Multiplication
1CA
(3)

[26]

QUESTION 3 [13 Marks]

Quest.  Solution  Explanation  Marks 
3.1.1  Perimeter = 8 ×500 ✓
= 4 000 ÷100✓ = 40 m ✓
1M multiplication
1M dividing by 100
1CA
(3) 
3.1.2  = 3,142×252 ✓
=1 963,75?
1S radius and 3,142
1A
(-1 for using calculator pi)
(2)
3.1.3  Area of the rectangle = 1 ?ℎ of the area of the sign post Type 2
                                     5 
=×196 3,75 ✓
   5
= 392,75 ??2 ✓
1S (Area from 3.1.2)
1CA
(2)
3.2.1  V = ??2ℎ h = 20 cm r = 10 cm ✓
V = 3,142×102×20 ✓
V = 6 284 ??3 ✓
1A (r = 10 cm)
1SF
1S
1CA
(3)
3.2.2  ?????? ?? ???? ????? = 2 × ?????? ?? ?ℎ? ?????(???? ?? ???? ???? ???? 2−???? ?? ???????? ?????????)
=      2 × 6284      
(1 963,75−392,75)✓✓
= 8 ✓
1SF
1S simplification
1CA
(3)

[13]

QUESTION 4 [16 Marks]

Quest  Solution  Explanation  Marks 
4.1.1   A ✓✓  2R  (2)
 4.1.2  Allow any value between 85 ‒ 90 km ✓✓  2 RM  (2)
 4.1.3  Highest point: UMLAAS RD ✓✓  2 RM  (2)
 4.1.4

Speed = ???????? ???? = 85 = 7,08 km/h
                                        12 
= 90= 7,5 km/h
   12 
Allow answer between (7,08 – 7,5) km/h ✓

1S
1CA
1A unit (km/h)
 (3)
4.2.1  Distance Cape Town to Durban
1 : 16 000 000
70 mm : 16 000 000 x 70 mm ✓
Distance = 16 000 000 x 70 ÷1000 000 ✓
=1 120 km ✓
1M multiplication
1M division
1A (with units)
 (3)
4.2.2   NW/????ℎ ???? ✓✓ 2 Reading Map  (2)
 4.2.3  8 ✓✓  2 Reading Map  (2)

[16]

QUESTION 5 [17 Marks]

Quest  Solution  Explanation  Marks 
5.1
5.1.1 
Bar graph ✓✓  2 RG  (2)
5.1.2  Ascending order
2,4; 2,4; 5,6; 9,7; 14,8; 17,4; 19, 7; 28,
0; 28,4; 31,6; 36,0 ✓
Median = 17,4 
1M order
1M middle value
2M middle values
 (2)
5.1.3  Mean = 2.3+0.7+5.1+17.3+25.6+28.8+15.8+13.4+15.5+5.5+4.6
                                              11✓
=134.6= 12,24 ✓
   11✓
M1 Addition
1M division by 11
1A
 (3)
5.1.4   The male age groups that have more than the upper quartile are 30‒34: ✓✓ and
35‒39 ✓
(36% and 28,8%)
2 RG
(Allocate 1 mark if % is given instead of age groups)
 (3)
5.2
5.2.1 
10 260 829 + 461 934 + 713 856+ 2 063 128 +
2 315 279+49 277 + 377 231+271 895 + 409 881=
16 923 309 ✓✓
1M addition
1A
 (2)
5.2.2  Value of B =1 266 102  x 100 ✓= 8,76 = 8,8%✓
                  14 450 161
OR
Value of B = 100% ‒ (57,0 + 3,1 +2,5 + 19,3 + 2,1 + 2,1 + 5,2) ✓= 8,8% ✓
1MA
1A
1M (100 ‒ the total of the other %)
CA
 (2)
5.2.3  P(flush toilet) = (60,6% + 2,7%) ✓✓
= 63,3% ✓
OR
P(flush toilet) = ????? ???ℎ ????ℎ ??????
                            ????? ?? ??????
= 10 722 763 ✓× 100 ✓=63,4% ✓
   16 923 309 
1M
1S
1A
1SF (numerator
and denominator)
1M multiplication with100
1CA 
 (3)

[17]

TOTAL: 100

Last modified on Friday, 09 July 2021 09:44