MATHEMATICAL LITERACY
PAPER 1
GRADE 12
NSC PAST PAPERS AND MEMOS
FEBRUARY/MARCH 2018
SYMBOL | EXPLANATION |
M | Method |
MA | Method with accuracy |
CA | Consistent accuracy |
A | Accuracy |
C | Conversion |
S | Simplification |
RT/RG | Reading from a table/graph/diagram |
SF | Correct substitution in a formula |
O | Opinion/Example/Definition/Explanation |
P | Penalty, e.g. for no units, incorrect rounding off, etc. |
R | Rounding off |
NPR | No penalty rounding or omitting units |
AO | Answer only, full marks |
Question 1 [30Marks] AO | |||||
Ques | Solution | Explanation | Topic/L | ||
1.1.1 | 3½ years ✔✔ A | 2A numerical period |
(2) | M | |
1.1.2 | Total Repayment Cost = R1 078,26 × 42 ✔ M/A | 1MA multiply term by instalment |
(2) | F | |
1.1.3 | ✔M | 1M calc. discount | (2) | F | |
1.2.1 | AD : CB = 10,9 : 9,45 ✔M | 1M ratio form (1: 0,87) OR (1,15 : 1) | (2) | MP | |
1.2.2 | ✔M/A | 1M/A subtracting all lengths | (2) | M | |
1.2.3 | Radius = 4,73 m ✔ M | 1M dividing by 2 | (2) | M | |
1.2.4 | ✔M/A | 1M/A multiply cost by correct distance | (2) | F | |
1.3.1 | C ✔✔A | 2A city | (2) | D | |
1.3.2 | Range = 8oC – (– 7oC)✔MA | 1MA subtracting correct values | (2) | D |
Ques | Solution | Explanation | Topic/L | ||
1.3.3 (a) | B ✔✔A | 2A city | (2) | P | |
1.3.3 (b) | Likely OR less likely ✔✔A | 2A correct words | (2) | P | |
1.4.1 | Bar graph ✔✔A | 2A correct type | (2) | D | |
1.4.2 | ✔✔A | 2A number in words | (2) | M | |
1.4.3 | Q 5 ✔✔A | 2A correct question | (2) | D | |
1.4.4 | Average time per mark = 180 min ✔MA | 1MA numerator and denominator | (2) | D | |
[30] |
Question 2 [44 Marks] | |||
Ques | Solution | Explanation | Topic/L |
2.1.1 | Stop order: an instruction to an employer or bank to pay / divert monthly or transfer regularly a certain amount to a person or an account. ✔✔O | 2O explanation (2) | F |
2.1.2 | ✔ M/A | 1M/A subtraction of correct value | F |
2.1.3 | Number of years (2017 – 2029) = 12 ✔ M/A | 1M/A calculating years | F |
2.1.4 | Total contribution value | 1M/A multiplying (5 and 12) | F |
2.1.5 | ✔✔A | 2A correct missing words (2) | F |
Ques | Solution | Explanation | Topic/L |
2.1.6 | ✔MA | 1MA percentage | F |
2.2.1 | Hourly overtime rate = R17,76 ×11/3 ✔MA | 1MA hours | F |
2.2.2 | ✔MA ✔A | 1MA increasing by 150% | F |
Ques | Solution | Explanation | Topic/L |
2.2.3 (a) | ✔A % increase = 17,76 -16,40 × 100% ✔M | 1M percentage | F |
2.2.3 (b) | A × 108,3% = 21,93 ✔RT | 1RT reading values | F |
Ques | Solution | Explanation | Topic/L |
2.2.4 | 2017 | 1RT reading value from the table | F |
2.3 | Total Income for the day | 2RT correct values | F |
Ques | Solution | Explanation | Topic/L |
2.4.1 | Employer provides people job/work for pay | 2O explanation (2) | F |
2.4.2 | ✔O ✔O | 2O reason (2) | F |
2.4.3(a) | ✔ RT ✔M | 1RT amounts |
F |
2.4.3 (b) | 1% of gross salary = R6 272,16 – R6 209,44 ✔MA | 1MA subtracting correct values | F |
[44] |
QUESTION 3 [25 MARKS] | |||
Ques | Solution | Explanation | Topic/L |
3.1.1 | ✔RT ✔RT ✔RT ✔RT | 2RT age | M |
3.1.2 | 8 kg ✔✔RT | 2RT mass/weight (2) | M |
3.1.3 | 12 months to 15 months ✔✔ RT | 2RT (one age in this range) (2) | M |
3.1.4 | February ✔✔A | 2Acorrect month (2) | M |
3.1.5 | BMI = weight (in kg) | 1SF correct values | M |
3.2.1 | Distance = 55 litre × 100 km ✔ MA | 1MA multiply by 100 | M L2 |
3.2.2 | ✔ SF Average speed = 189 = 189 | 1C to hours | M |
3.3.1 | ✔ SF | 1SF correct substitution | M |
3.3.2 | P(U)= 3 12 ✔ A | 1A numerator | P |
[25] |
QUESTION 4 [19 MARKS] | |||||
Ques | Solution | Explanation | Topic/L | ||
4.1.1 | ✔ A ✔ A | 1A N10 | (2) | MP | |
4.1.2 | ✔✔ RT | 2RTcorrect name | (2) | MP | |
4.1.3 | Kirkwood ✔✔A | 2A correct hometown | (2) | MP | |
4.1.4 | ✔RT ✔ M | 1RT correct distances 1M adding | (3) | MP L2 | |
4.2.1 | 3750 mm ✔✔ A | 2A distance | (2) | MP | |
4.2.2 | = 3 550 mm + 3750 mm✔A | 1A adding 3 correct distances | (2) | MP | |
4.2.3 | Living room. ✔✔ A | 2A | (2) | MP | |
4.2.4 | Bedroom 2 ✔✔A | 2A room | (2) | MP | |
4.2.5 | Wash basin/sink/water basin OR Shower ✔✔ A | 2A any item | (2) | MP | |
[19] |
QUESTION 5 [32MARKS] | |||||
Ques | Solution | Explanation | Topic/L | ||
5.1.1 | Numerical ✔✔A | 2A answer | (2) | D | |
5.1.2 | 50% ✔✔A | 2A answer | (2) | D | |
5.1.3 | Range = Maximum - minimum ✔M | 1M range concept (can be implied)
| (3) | D | |
5.1.4 | Median % = 67 + 69 🗸M | 1M concept of median | (2) | D | |
5.1.5 | Inter-quartile range = Q3 - Q1✔M | 1M IQR concept(implied) | (3) | D | |
5.1.6 | 66 🗸🗸A | 2A mode | (2) | D | |
5.1.7 | Mean = sum of the marks | 1MA mean concept (implied) 1A adding values 1CA value of H | (3) | D | |
5.1.8 | P (equal marks) = 13 🗸A | 1A numerator | (3) | P |
Ques | Solution | Explanation | Topic/L |
5.2.1 | 🗸MA | 1MA adding all Non- literate adults | D L1 |
5.2.2 | 🗸 RT | 1RT numerator and denominator 1M multiply by 100 1CA answer | D |
5.2.3 | Non Literate: Literacy = 650 033:1 956 497🗸 RT = 650 033 : 1956 497 🗸MA 650 033 650 033 = 1 : 3,009842577 ≈1 : 3 or 1 : 3,01 or 1 : 3,0099 🗸 CA | 1RT both values | D |
5.2.4 | 🗸🗸MA 244 282; 609 029; 760 029;784 347; 922 171; 1 120 567; 1 762 494; 1 956 497; 4 013 463 | 2MA arranging (2) | D |
5.2.5 | Northern Cape (NC) 🗸🗸A | 2A correct province (2) | D |
[32] | |||
TOTAL: | 150 |